Atomic Foundations of Matter – Complete Question Bank
NCERT-aligned • Exemplar-style • Competency Based • HOTS • Olympiad Practice
Detailed answers and explanations are provided below every question. Questions progress from fundamental concepts to higher-order application and reasoning.
Chapter Coverage
Section A – 30 Multiple Choice Questions
Difficulty gradually rises from NCERT fundamentals to competency and Olympiad-style reasoning.
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Correct option: (C) Antoine Lavoisier.
Lavoisier proposed the Law of Conservation of Mass in 1789. According to this law, matter can neither be created nor destroyed during a chemical reaction. Therefore, in a properly closed system, the total mass of reactants equals the total mass of products.
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Correct option: (B) Carbon dioxide escapes.
The reaction produces carbon dioxide gas. In an open arrangement, some carbon dioxide leaves the system and is therefore not included in the final weighing. The apparent loss of mass does not violate conservation of mass because the escaped gas still possesses mass.
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Correct option: (B) 1 : 8.
The hydrogen-to-oxygen mass ratio in pure water is always 1:8, irrespective of whether the water originally came from a river, borewell, ocean or another source. This illustrates the Law of Constant or Definite Proportions.
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Correct option: (C) 71 g.
Doubling the amount of sodium from 23 g to 46 g requires the chlorine mass to double from 35.5 g to 71 g so that the fixed composition remains unchanged.
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Correct option: (B).
Dalton proposed that all matter is made up of very small particles called atoms. He also stated that atoms participate in chemical reactions, are not created or destroyed in such reactions and combine in simple whole-number ratios.
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Correct option: (B).
A molecule is electrically neutral, consists of more than one atom, can exist independently and exhibits the properties of the substance. H2, O2, HCl and H2O are examples.
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Correct option: (B).
Each hydrogen atom has one electron and requires one more to complete its K shell. Each contributes one electron to a shared pair. Therefore H2 contains a single covalent bond: H—H.
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Correct option: (B).
Oxygen has six valence electrons and requires two more for an octet. Two oxygen atoms therefore share two electrons each, producing two shared electron pairs and a double covalent bond, O=O.
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Correct option: (C) N≡N.
Each nitrogen atom requires three additional electrons to complete its octet. Two nitrogen atoms share three pairs of electrons. Therefore a triple covalent bond is formed.
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Correct option: (B).
Neon has atomic number 10 and electronic configuration 2,8. Its valence shell is already complete, so it normally has no tendency to gain, lose or share electrons merely to attain an octet.
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Correct option: (C) dinitrogen tetroxide.
The prefix di- indicates two nitrogen atoms. Four oxygen atoms are indicated by tetra-, but before “oxide” the final vowel is dropped, producing tetroxide, not tetraoxide.
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Correct option: (C).
The first element retains its normal name. The second element is changed to fluoride and the prefix hexa- shows that six fluorine atoms are present. “Mono-” is normally omitted for the first element.
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Correct option: (B) 10.
A sodium atom forms Na+ by losing one electron. The number of protons remains 11 while electrons decrease from 11 to 10, giving a net charge of +1.
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Correct option: (C) 18 electrons.
Neutral chlorine has 17 electrons. It gains one electron to complete its octet, forming Cl−. It then contains 17 protons and 18 electrons.
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Correct option: (C) 6.
Sodium chloride does not normally exist as separate NaCl molecules. The ions form a repeating three-dimensional crystal structure in which each sodium ion is surrounded by six chloride ions, and vice versa.
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Correct option: (D) S2−.
Sulfur requires two additional electrons to complete its octet. On gaining two electrons, it acquires two units of negative charge and forms the sulfide ion S2−.
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Correct option: (C) nitrate, NO3−.
A polyatomic ion contains two or more atoms acting together as a charged unit. Nitrate contains one nitrogen and three oxygen atoms and carries a net charge of −1.
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Correct option: (B) MgCl2.
Magnesium forms Mg2+ while chlorine forms Cl−. Two chloride ions are required to balance one magnesium ion:
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Correct option: (C).
Aluminium forms Al3+ and oxygen forms O2−. The smallest charge-balanced combination contains two aluminium ions (+6) and three oxide ions (−6), hence Al2O3.
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Correct option: (B).
OH− is a polyatomic ion. Mg2+ requires two hydroxide ions for charge balance. The subscript 2 must apply to the entire OH group, so brackets are necessary: Mg(OH)2.
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Correct option: (D).
Al3+ and SO42− must combine so that total positive and negative charges are equal. The LCM of 3 and 2 is 6, requiring two aluminium ions and three sulfate ions.
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Correct option: (B).
NaCl contains ions even in the solid state, but they are strongly held at fixed positions in its crystal lattice. Since charged particles cannot move freely through the solid, electric current cannot be carried through it.
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Correct option: (B).
When an ionic compound dissolves in water, its ions become free to move through the solution. These mobile charged particles carry electric current.
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Correct option: (B).
Sugar is a covalent substance. Its particles may disperse in water, but it does not produce the freely moving ions required for conduction. Solubility and electrical conductivity are therefore not the same property.
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Correct option: (B).
Oppositely charged ions in an ionic crystal experience strong electrostatic attractions. Considerable energy is required to overcome these forces, so ionic compounds generally have high melting and boiling points.
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Correct option: (C) 63 u.
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Correct option: (C) 16 u.
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Correct option: (C) 58 u.
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Correct option: (B) Na+.
Eleven protons identify the element as sodium because atomic number = number of protons = 11. The species has one fewer electron than protons, so its charge is +1.
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Correct option: (B) A2B, ionic.
A has one valence electron and tends to lose it, forming A+. B has six valence electrons and tends to gain two, forming B2−. Two A+ ions are therefore required for every B2− ion.
Section B – 15 Two-Mark Questions
Short-answer questions testing concepts, reasoning and brief calculations.
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- The reaction produces carbon dioxide gas.
- In the open flask, CO2 escapes and is not included in the final mass. In the closed arrangement, the balloon traps the gas, so the mass of the complete system remains constant.
Thus, the observations support the Law of Conservation of Mass.
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In a compound, constituent elements are chemically combined in a definite fixed ratio by mass. A mixture is formed by physically combining substances, and its components may generally be present in variable proportions. Therefore the definite-proportion law is characteristic of compounds, not mixtures.
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- Conservation of mass is explained by atoms being rearranged rather than created or destroyed during a chemical reaction.
- Constant proportions are explained by atoms of elements combining in fixed simple whole-number ratios to form a given compound.
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An atom is electrically neutral because it contains equal numbers of protons and electrons. An ion is charged because an atom or group of atoms has lost or gained electrons. Loss produces a cation, while gain produces an anion.
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Hydrogen has one valence electron and needs one more for a duplet. Chlorine has seven valence electrons and needs one more for an octet. Each contributes one electron to one shared pair.
Hence HCl contains a single covalent bond.
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Each oxygen atom has six valence electrons and requires two more to complete an octet. Each oxygen therefore shares two electrons with the other, producing two shared electron pairs. Two shared pairs constitute a double bond, represented as O=O.
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- Cation: Positively charged ion formed by loss of electron(s), e.g. Na+.
- Anion: Negatively charged ion formed by gain of electron(s), e.g. Cl−.
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Sodium, with configuration 2,8,1, loses one electron to form Na+. Chlorine, with configuration 2,8,7, accepts this electron to form Cl−. Electrostatic attraction between the oppositely charged ions forms an ionic bond.
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Sodium chloride forms a continuous three-dimensional lattice of Na+ and Cl− ions rather than separate NaCl molecules. NaCl therefore represents the simplest whole-number ratio, 1:1, of sodium and chloride ions and is called a formula unit.
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- The first element retains its normal name; the second generally ends in -ide.
- Prefixes such as mono-, di-, tri-, tetra-, penta- and hexa- indicate the number of atoms. Mono- is generally omitted for the first element.
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Magnesium forms Mg2+ and oxygen forms O2−. Direct criss-crossing gives Mg2O2, but an ionic formula must represent the simplest whole-number ratio. Dividing both subscripts by 2 gives MgO.
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OH− is one complete polyatomic hydroxide ion. Three hydroxide ions are needed to balance Al3+. Brackets show that the subscript 3 applies to the entire OH group: Al(OH)3. AlOH3 would incorrectly suggest one oxygen and three separate hydrogen atoms.
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In a solid ionic crystal, ions occupy fixed positions and cannot move through the lattice. On melting or dissolving in water, the ions become mobile. These moving charged particles carry electric current.
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Answer: 74.5 u.
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Any two suitable applications include:
- Generation of electricity in nuclear power plants.
- Medicine.
- Scientific research.
- Space exploration.
The chapter also highlights Raja Ramanna’s contribution to India’s nuclear energy programme and its peaceful development.
Section C – 20 Three-Mark Questions
Application, experiment design, bonding, formula writing and numerical reasoning.
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- Place dilute HCl in a conical flask and zinc separately in a balloon or another compartment attached to the flask without mixing them initially.
- Seal the system and record its total initial mass. Allow zinc to react with HCl while ensuring the produced hydrogen gas cannot escape.
- After the reaction is complete, weigh the entire closed system again. The final mass should equal the initial mass within experimental uncertainty.
This demonstrates that mass is conserved even though a gas is produced.
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Since total mass of reactants = total mass of products = 11.3 g, the reaction obeys the Law of Conservation of Mass.
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S : O = 2 : 3
The fixed 2:3 ratio illustrates the Law of Constant Proportions.
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Yes. X obtains a ratio of 4:1. For Y:
Both ratios reduce to the same value. Therefore both samples have the same composition by mass, supporting the Law of Constant Proportions.
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Any three:
- All matter consists of very small particles called atoms.
- Atoms cannot be created or destroyed during a chemical reaction.
- Atoms of a given element are identical in mass and chemical properties according to Dalton’s original theory.
- Atoms of different elements have different masses and chemical properties.
- Atoms combine in simple whole-number ratios to form compounds.
- The relative numbers and kinds of atoms remain constant in a particular compound.
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- Nitrogen has atomic number 7 and electronic configuration 2,5.
- Each nitrogen atom needs three more electrons for an octet.
- Two nitrogen atoms share three pairs of electrons, producing a triple covalent bond.
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- Electronic configuration of F = 2,7.
- Each fluorine atom needs one electron to complete its octet.
- Two fluorine atoms share one electron each, producing one shared electron pair and therefore a single covalent bond.
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- Oxygen has six valence electrons and requires two more.
- Each hydrogen atom has one electron and needs one more for a duplet.
- Oxygen shares one electron pair with each of two hydrogen atoms, forming two O—H single covalent bonds.
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Carbon requires four electrons to complete its octet while each oxygen requires two. Carbon therefore shares two pairs of electrons with each of two oxygen atoms.
Thus one carbon atom combines with two oxygen atoms, giving CO2 with two double covalent bonds.
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- H valency 1, S valency 2 → H2S.
- N valency 3, H valency 1 → NH3.
- C valency 4, Cl valency 1 → CCl4.
The valencies are crossed over as subscripts and reduced where required.
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- CO – carbon monoxide
- CO2 – carbon dioxide
- CS2 – carbon disulfide
- PCl3 – phosphorus trichloride
- SF6 – sulfur hexafluoride
- N2O5 – dinitrogen pentoxide
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Calcium loses two valence electrons to form Ca2+. Each chlorine atom accepts one electron to form Cl−. Therefore two chloride ions are necessary to balance the +2 charge of one calcium ion.
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- Potassium loses one electron → K+. It combines 1:1 with Cl− → KCl.
- Calcium loses two electrons → Ca2+. It requires two Cl− ions → CaCl2.
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Each sodium atom loses one electron and forms Na+. Sulfur needs two electrons and forms S2−. Therefore two sodium atoms provide the two electrons required by one sulfur atom.
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| Ion | Formula | Valency / Charge magnitude |
|---|---|---|
| Hydroxide | OH− | 1 |
| Nitrate | NO3− | 1 |
| Carbonate | CO32− | 2 |
| Sulfate | SO42− | 2 |
| Ammonium | NH4+ | 1 |
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- Fe3+ + OH− → Fe(OH)3
- K+ + CO32− → K2CO3
- Al3+ + SO42− → Al2(SO4)3
In each case, the total positive and negative charges in the compound are equal.
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| Property | Ionic | Covalent |
|---|---|---|
| Solubility | Generally soluble in water | Many are insoluble in water but may dissolve in petrol/kerosene |
| Conductivity | Conduct when molten or in aqueous solution | Generally poor conductors |
| Melting/boiling point | Generally high | Usually comparatively low |
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- NaCl and copper sulfate form mobile ions in aqueous solution, so their solutions conduct electricity.
- Sugar may dissolve but does not produce ions, so its solution does not conduct appreciably.
- Camphor and naphthalene are covalent substances and are generally insoluble in water and non-conducting.
Therefore conductivity depends on the presence of mobile charged particles, not simply on whether a substance appears to dissolve.
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Formula unit mass = 164 u.
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| Species | Protons | Electrons | Neutrons |
|---|---|---|---|
| 27Al | 13 | 13 | 27 − 13 = 14 |
| 80Br− | 35 | 36 | 80 − 35 = 45 |
| 201Hg2+ | 80 | 78 | 201 − 80 = 121 |
Negative charge means electron gain; positive charge means electron loss. Ion formation does not alter the number of neutrons.
Section D – 15 Four-Mark Questions
Long-answer, competency, experimental and higher-order reasoning questions.
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- Open arrangement: Vinegar is placed in a flask and baking soda is added. Brisk effervescence occurs as CO2 forms.
- The gas escapes into the surroundings, so the measured final mass of the apparatus may be smaller than the initial mass.
- Closed arrangement: Baking soda is placed in a balloon attached securely to the flask containing vinegar. The system is weighed before mixing.
- When the substances react, CO2 inflates the balloon but cannot escape. The total final mass remains equal to the initial mass within experimental error.
The experiment shows that an apparent loss in an open system results from matter leaving the measured system, not from destruction of matter.
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- Keep sodium sulfate solution in flask A and barium chloride solution in flask B and record the combined mass.
- Transfer one solution into the other. A white precipitate of barium sulfate forms along with sodium chloride.
- Place both flasks back on the balance. The total mass remains essentially unchanged, demonstrating conservation of mass.
- Precaution: Both flasks should remain part of the weighing before and after transfer because traces of solution may remain stuck to the flask walls.
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1. Law of Conservation of Mass:
Total mass before a chemical reaction equals total mass after the reaction. Example: if reactants have masses 4.0 g and 2.92 g:
If products are 1.76 g, 0.72 g and 4.44 g:
2. Law of Constant Proportions:
A given compound always contains its constituent elements in a fixed ratio by mass. In water H:O = 1:8. Thus 18 g water contains:
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- A compound would no longer possess a definite composition.
- Samples obtained from different places could contain different mass ratios of their elements.
- The Law of Constant Proportions would not hold for that substance.
- Reliable chemical formulae representing definite numbers or ratios of atoms would lose their meaning for the supposed compound.
Fixed composition is therefore one of the key characteristics that distinguish a pure compound from a variable mixture.
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| Molecule | Need of each atom | Shared pairs | Representation |
|---|---|---|---|
| H2 | Each H needs 1 electron | 1 | H—H |
| Cl2 | Each Cl needs 1 electron | 1 | Cl—Cl |
| O2 | Each O needs 2 electrons | 2 | O=O |
| N2 | Each N needs 3 electrons | 3 | N≡N |
| HCl | H needs 1; Cl needs 1 | 1 | H—Cl |
In every case the atoms gain greater stability through electron sharing.
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- The first element keeps its ordinary name; the second generally ends in -ide.
- Prefixes mono-, di-, tri-, tetra-, penta-, hexa-, etc. indicate atom numbers.
- Mono- is usually omitted before the first element: CO is carbon monoxide, not monocarbon monoxide.
- Where necessary, the final vowel of a prefix is dropped before “oxide”: N2O4 is dinitrogen tetroxide, while CO is monoxide.
Other examples: CO2 carbon dioxide, PCl3 phosphorus trichloride and SF6 sulfur hexafluoride.
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Magnesium chloride:
2Cl + 2e− → 2Cl−
Mg2+ + 2Cl− → MgCl2
Calcium oxide:
O + 2e− → O2−
Ca2+ + O2− → CaO
Both contain oppositely charged ions held together by electrostatic attraction. This attraction constitutes the ionic bond.
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- Ionic compounds consist of a regular three-dimensional arrangement of oppositely charged ions.
- Strong electrostatic attractions hold the ions together, so a large amount of energy is required to separate them. This gives generally high melting and boiling points.
- In the solid state, ions are fixed in position and cannot carry current.
- When molten or dissolved, ions become mobile and can carry electric charge, so the substance conducts.
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- Magnesium hydroxide – Mg(OH)2
- Calcium carbonate – CaCO3
- Aluminium hydroxide – Al(OH)3
- Aluminium sulfate – Al2(SO4)3
Brackets are used when two or more of the same polyatomic ion are required. Thus (OH)3 means three complete OH− ions, and (SO4)3 means three complete sulfate ions.
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| Compound | Ions | Formula |
|---|---|---|
| Ferric chloride | Fe3+, Cl− | FeCl3 |
| Cuprous oxide | Cu+, O2− | Cu2O |
| Aluminium nitrate | Al3+, NO3− | Al(NO3)3 |
| Ammonium sulfate | NH4+, SO42− | (NH4)2SO4 |
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- Test each substance for solubility in water and in non-aqueous solvents such as petrol/kerosene using appropriate safety precautions.
- NaCl and CuSO4 are ionic examples and are generally water-soluble.
- Their aqueous solutions conduct because mobile ions are present.
- Camphor and naphthalene are covalent and generally dissolve better in non-aqueous solvents; sugar is a useful exception because it dissolves in water but does not ionise and therefore does not conduct.
Thus multiple properties must be considered rather than using water-solubility alone.
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For C:O = 3:8:
CO2 = 15 + 40 = 55 g
The calculation applies both constant composition and conservation of mass.
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- H2O = 2(1) + 16 = 18 u
- CO2 = 12 + 2(16) = 44 u
- Na2O = 2(23) + 16 = 62 u
- Mg(OH)2 = 24 + 2(16 + 1) = 58 u
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- Atomic number = number of protons = 11.
- Mass number = protons + neutrons = 11 + 12 = 23.
- It has 11 protons but only 10 electrons, so charge = +1.
- Electronic configuration for 10 electrons = 2,8.
- Atomic number 11 corresponds to sodium, so the species is 23Na+.
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- A has five valence electrons and requires three more to complete an octet.
- B has seven valence electrons and requires one more.
- Both have more than four valence electrons, so electron sharing is expected rather than one readily donating several electrons to the other.
- A can share with three B atoms. The simplest formula is therefore AB3, with covalent bonding.
Section E – 5 Competency-Based Case Studies
Integrated questions requiring interpretation, calculation and scientific reasoning.
Case Study 1 – The Inflating Balloon Experiment
(a) Name the gas responsible for inflating the balloon.
(b) Why should the final mass be approximately equal to the initial mass?
(c) What would happen to the measured mass if the reaction were performed in an open beaker?
(d) State the scientific law demonstrated.
(e) Why should the balloon and flask both remain part of the system during weighing?
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(a) Carbon dioxide, CO2.
(b) The balloon traps the gas. Since no significant matter leaves the closed system, all reactant and product matter remains on the balance. Hence initial and final masses should be equal within experimental uncertainty.
(c) The measured final mass would appear smaller because carbon dioxide would escape into the surroundings.
(d) Law of Conservation of Mass: matter can neither be created nor destroyed in a chemical reaction.
(e) Traces of material may remain in or on the balloon. Removing any component would change what is being weighed and could introduce experimental error.
Case Study 2 – Is Water Always the Same?
(a) Which law is illustrated?
(b) How much oxygen is present with 3 g hydrogen?
(c) What mass of water contains 5 g hydrogen?
(d) If a sample claimed to be pure water contains hydrogen and oxygen in a 1:6 ratio, what conclusion can be drawn?
(e) Why does source not affect the composition of purified water?
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(a) Law of Constant Proportions or Law of Definite Proportions.
(b)
For 3 g H, oxygen = 3 × 8 = 24 g.
(c)
Mass of water = 5 + 40 = 45 g.
(d) A 1:6 H:O ratio does not correspond to the fixed composition of pure water. The sample, measurement or identification would therefore require investigation.
(e) Pure water is a definite chemical compound. Its constituent elements occur in a fixed ratio by mass irrespective of its geographical source.
Case Study 3 – Which Solution Lights the Bulb?
(a) Why do NaCl and CuSO4 solutions conduct electricity?
(b) Why does sugar solution fail to conduct even though sugar dissolves?
(c) Would solid NaCl conduct? Explain.
(d) Predict whether molten NaCl conducts electricity.
(e) Name one important safety precaution for the experiment.
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(a) These ionic compounds provide mobile ions in aqueous solution. The ions carry electric charge through the liquid.
(b) Sugar is covalent. Although it can dissolve, it does not produce the freely moving ions needed to conduct electric current.
(c) No. In solid NaCl, Na+ and Cl− ions are held in fixed positions in a crystal lattice and cannot migrate.
(d) Yes. On melting, the ions become mobile and can carry current.
(e) Use a low-voltage battery and do not touch connected electrodes. Petrol and kerosene, if used during solubility tests, must also be handled away from flames because they are flammable.
Case Study 4 – Building Ionic Compounds
(a) Write the formula formed from Al3+ and Cl−.
(b) Write the formula formed from Mg2+ and OH−.
(c) Write the formula formed from NH4+ and SO42−.
(d) Why are brackets required in two of the answers above?
(e) Why are ionic formulae written in the simplest whole-number ratio?
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(a) AlCl3.
(b) Mg(OH)2.
(c) (NH4)2SO4.
(d) OH− and NH4+ are polyatomic ions. When more than one complete polyatomic ion is required, brackets ensure that the subscript applies to the whole ion rather than just its final element.
(e) Ionic compounds form extended crystal structures rather than separate molecules. Their formula indicates the simplest whole-number ratio of oppositely charged ions needed for overall electrical neutrality.
Case Study 5 – Mystery Elements A and B
(a) How many electrons will A tend to lose?
(b) What charge will A acquire?
(c) How many electrons will each B atom tend to gain?
(d) Predict the formula of the compound.
(e) Predict its bonding type and two likely general properties.
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(a) A has two valence electrons and tends to lose both to achieve a stable configuration.
(b) It forms A2+.
(c) Each B atom has seven valence electrons and gains one electron, forming B−.
(d) Two B− ions are required to balance one A2+ ion:
(e) Electron transfer produces an ionic compound. It would generally be expected to have a comparatively high melting point and conduct electricity when molten or when its ions are mobile in aqueous solution. In its solid state, the ions would remain fixed and it would not normally conduct electricity.
Final Challenge – Mixed Revision
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X is most likely ionic.
- Strong electrostatic attractions explain its high melting point.
- Ions are fixed in the solid state, so the solid does not conduct.
- When molten, the ions become mobile and conduct electricity.
Y is most likely covalent.
- Many covalent compounds have relatively low melting and boiling points.
- They generally do not provide mobile ions and therefore usually do not conduct electricity.
High-Yield Revision Points
- Conservation of mass: total mass of reactants = total mass of products.
- Constant proportions: a given compound contains its elements in a fixed mass ratio.
- Covalent bond: formed by sharing electron pairs.
- Ionic bond: electrostatic attraction between oppositely charged ions formed after electron transfer.
- Cation: positive ion; anion: negative ion.
- Ionic compounds form extended crystal structures rather than independent molecules.
- Solid ionic compounds generally do not conduct because ions are fixed.
- Molten or dissolved ionic compounds conduct because their ions can move.
- Covalent substances generally do not provide mobile ions.
- Use brackets when more than one of the same polyatomic ion occurs in a formula.
- Always reduce ionic formulae to the simplest whole-number ratio.
- Molecular mass is used for molecules; formula unit mass is used for ionic formula units.

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