SK Tuitions • Class 9 CBSE Science

Atomic Foundations of Matter – Complete Question Bank

NCERT-aligned • Exemplar-style • Competency Based • HOTS • Olympiad Practice

Detailed answers and explanations are provided below every question. Questions progress from fundamental concepts to higher-order application and reasoning.

30MCQs
152 Markers
203 Markers
154 Markers
5Case Studies

Chapter Coverage

Law of Conservation of Mass
Law of Constant Proportions
Dalton’s Atomic Theory
Atoms & Molecules
Chemical Bonds
Covalent Bonding
Single, Double & Multiple Bonds
Ionic Bonding
Cations & Anions
Crystal Lattice
Polyatomic Ions
Naming Covalent Compounds
Naming Ionic Compounds
Writing Chemical Formulae
Valency & Charge Balance
Properties of Ionic Compounds
Properties of Covalent Compounds
Electrical Conductivity
Solubility & Melting Points
Molecular Mass
Formula Unit Mass

Section A – 30 Multiple Choice Questions

Difficulty gradually rises from NCERT fundamentals to competency and Olympiad-style reasoning.

1
The Law of Conservation of Mass was proposed by:
  • (A) John Dalton
  • (B) Joseph Proust
  • (C) Antoine Lavoisier
  • (D) Ernest Rutherford
View Detailed Answer

Correct option: (C) Antoine Lavoisier.

Lavoisier proposed the Law of Conservation of Mass in 1789. According to this law, matter can neither be created nor destroyed during a chemical reaction. Therefore, in a properly closed system, the total mass of reactants equals the total mass of products.

2
Vinegar reacts with baking soda in a flask. Why may the final mass appear smaller if the flask is open?
  • (A) Matter is destroyed
  • (B) Carbon dioxide escapes
  • (C) Vinegar loses its mass
  • (D) Baking soda becomes weightless
View Detailed Answer

Correct option: (B) Carbon dioxide escapes.

The reaction produces carbon dioxide gas. In an open arrangement, some carbon dioxide leaves the system and is therefore not included in the final weighing. The apparent loss of mass does not violate conservation of mass because the escaped gas still possesses mass.

3
Pure water obtained from different sources always contains hydrogen and oxygen in which mass ratio?
  • (A) 1 : 4
  • (B) 1 : 8
  • (C) 2 : 1
  • (D) 8 : 1
View Detailed Answer

Correct option: (B) 1 : 8.

The hydrogen-to-oxygen mass ratio in pure water is always 1:8, irrespective of whether the water originally came from a river, borewell, ocean or another source. This illustrates the Law of Constant or Definite Proportions.

4
Sodium and chlorine occur in sodium chloride in the mass ratio 23:35.5. How much chlorine is required for 46 g sodium?
  • (A) 35.5 g
  • (B) 46 g
  • (C) 71 g
  • (D) 92 g
View Detailed Answer

Correct option: (C) 71 g.

Chlorine required = (35.5/23) × 46 = 71 g

Doubling the amount of sodium from 23 g to 46 g requires the chlorine mass to double from 35.5 g to 71 g so that the fixed composition remains unchanged.

5
Which statement represents a postulate of Dalton’s Atomic Theory?
  • (A) Atoms are created during reactions.
  • (B) All matter consists of tiny particles called atoms.
  • (C) All elements contain identical atoms.
  • (D) Atoms combine only in fractional numbers.
View Detailed Answer

Correct option: (B).

Dalton proposed that all matter is made up of very small particles called atoms. He also stated that atoms participate in chemical reactions, are not created or destroyed in such reactions and combine in simple whole-number ratios.

6
Which description best defines a molecule?
  • (A) Any charged particle
  • (B) An electrically neutral entity of more than one atom capable of independent existence
  • (C) A positively charged atom
  • (D) A three-dimensional arrangement of ions only
View Detailed Answer

Correct option: (B).

A molecule is electrically neutral, consists of more than one atom, can exist independently and exhibits the properties of the substance. H2, O2, HCl and H2O are examples.

7
The bond between the two atoms in H2 is formed by:
  • (A) Transfer of two electrons
  • (B) Sharing one pair of electrons
  • (C) Attraction between ions
  • (D) Sharing two pairs of electrons
View Detailed Answer

Correct option: (B).

Each hydrogen atom has one electron and requires one more to complete its K shell. Each contributes one electron to a shared pair. Therefore H2 contains a single covalent bond: H—H.

8
The oxygen molecule O2 contains:
  • (A) One shared pair
  • (B) Two shared pairs
  • (C) Three shared pairs
  • (D) No shared electrons
View Detailed Answer

Correct option: (B).

Oxygen has six valence electrons and requires two more for an octet. Two oxygen atoms therefore share two electrons each, producing two shared electron pairs and a double covalent bond, O=O.

9
Nitrogen has five valence electrons. The most suitable representation of N2 is:
  • (A) N—N
  • (B) N=N
  • (C) N≡N
  • (D) N+N
View Detailed Answer

Correct option: (C) N≡N.

Each nitrogen atom requires three additional electrons to complete its octet. Two nitrogen atoms share three pairs of electrons. Therefore a triple covalent bond is formed.

10
Why does neon generally neither gain, lose nor share valence electrons?
  • (A) It has no nucleus.
  • (B) Its electronic configuration is already stable.
  • (C) It has only one electron.
  • (D) It is a metal.
View Detailed Answer

Correct option: (B).

Neon has atomic number 10 and electronic configuration 2,8. Its valence shell is already complete, so it normally has no tendency to gain, lose or share electrons merely to attain an octet.

11
The correct name of N2O4 is:
  • (A) Nitrogen oxide
  • (B) Dinitrogen tetraoxide
  • (C) Dinitrogen tetroxide
  • (D) Nitrogen tetroxide
View Detailed Answer

Correct option: (C) dinitrogen tetroxide.

The prefix di- indicates two nitrogen atoms. Four oxygen atoms are indicated by tetra-, but before “oxide” the final vowel is dropped, producing tetroxide, not tetraoxide.

12
SF6 is correctly named:
  • (A) Sulfur fluoride
  • (B) Monosulfur fluoride
  • (C) Sulfur hexafluoride
  • (D) Sulfur six fluoride
View Detailed Answer

Correct option: (C).

The first element retains its normal name. The second element is changed to fluoride and the prefix hexa- shows that six fluorine atoms are present. “Mono-” is normally omitted for the first element.

13
A sodium atom has 11 protons and 11 electrons. How many electrons does Na+ have?
  • (A) 9
  • (B) 10
  • (C) 11
  • (D) 12
View Detailed Answer

Correct option: (B) 10.

A sodium atom forms Na+ by losing one electron. The number of protons remains 11 while electrons decrease from 11 to 10, giving a net charge of +1.

14
Chlorine has atomic number 17. The chloride ion Cl contains:
  • (A) 16 electrons
  • (B) 17 electrons
  • (C) 18 electrons
  • (D) 19 electrons
View Detailed Answer

Correct option: (C) 18 electrons.

Neutral chlorine has 17 electrons. It gains one electron to complete its octet, forming Cl. It then contains 17 protons and 18 electrons.

15
In the sodium chloride crystal structure, each Na+ ion is surrounded by:
  • (A) 2 Cl ions
  • (B) 4 Cl ions
  • (C) 6 Cl ions
  • (D) 8 Cl ions
View Detailed Answer

Correct option: (C) 6.

Sodium chloride does not normally exist as separate NaCl molecules. The ions form a repeating three-dimensional crystal structure in which each sodium ion is surrounded by six chloride ions, and vice versa.

16
A sulfur atom with six valence electrons is most likely to form:
  • (A) S+
  • (B) S2+
  • (C) S
  • (D) S2−
View Detailed Answer

Correct option: (D) S2−.

Sulfur requires two additional electrons to complete its octet. On gaining two electrons, it acquires two units of negative charge and forms the sulfide ion S2−.

17
Which is a polyatomic ion?
  • (A) Na+
  • (B) Cl
  • (C) NO3
  • (D) O2−
View Detailed Answer

Correct option: (C) nitrate, NO3.

A polyatomic ion contains two or more atoms acting together as a charged unit. Nitrate contains one nitrogen and three oxygen atoms and carries a net charge of −1.

18
The correct formula for magnesium chloride is:
  • (A) MgCl
  • (B) MgCl2
  • (C) Mg2Cl
  • (D) Mg2Cl2
View Detailed Answer

Correct option: (B) MgCl2.

Magnesium forms Mg2+ while chlorine forms Cl. Two chloride ions are required to balance one magnesium ion:

Mg2+ + 2Cl → MgCl2
19
Which formula correctly represents aluminium oxide?
  • (A) AlO
  • (B) AlO2
  • (C) Al2O3
  • (D) Al3O2
View Detailed Answer

Correct option: (C).

Aluminium forms Al3+ and oxygen forms O2−. The smallest charge-balanced combination contains two aluminium ions (+6) and three oxide ions (−6), hence Al2O3.

20
Why are brackets required in Mg(OH)2?
  • (A) Magnesium is polyatomic.
  • (B) Two complete hydroxide ions are present.
  • (C) Oxygen has no valency.
  • (D) Hydrogen is positively charged.
View Detailed Answer

Correct option: (B).

OH is a polyatomic ion. Mg2+ requires two hydroxide ions for charge balance. The subscript 2 must apply to the entire OH group, so brackets are necessary: Mg(OH)2.

21
The formula of aluminium sulfate is:
  • (A) AlSO4
  • (B) Al2SO4
  • (C) Al(SO4)3
  • (D) Al2(SO4)3
View Detailed Answer

Correct option: (D).

Al3+ and SO42− must combine so that total positive and negative charges are equal. The LCM of 3 and 2 is 6, requiring two aluminium ions and three sulfate ions.

22
Solid sodium chloride does not conduct electricity because:
  • (A) it contains no ions.
  • (B) its ions are fixed in the lattice.
  • (C) sodium has no charge.
  • (D) chlorine atoms absorb electricity.
View Detailed Answer

Correct option: (B).

NaCl contains ions even in the solid state, but they are strongly held at fixed positions in its crystal lattice. Since charged particles cannot move freely through the solid, electric current cannot be carried through it.

23
An aqueous solution of sodium chloride conducts electricity mainly because:
  • (A) water becomes a metal.
  • (B) Na+ and Cl ions become mobile.
  • (C) salt atoms disappear.
  • (D) electrons leave all water molecules.
View Detailed Answer

Correct option: (B).

When an ionic compound dissolves in water, its ions become free to move through the solution. These mobile charged particles carry electric current.

24
Sugar dissolves in water but the solution generally does not conduct electricity. The best explanation is:
  • (A) Sugar is insoluble in water.
  • (B) Sugar provides no mobile ions in solution.
  • (C) Water destroys electricity.
  • (D) Sugar forms metallic bonds.
View Detailed Answer

Correct option: (B).

Sugar is a covalent substance. Its particles may disperse in water, but it does not produce the freely moving ions required for conduction. Solubility and electrical conductivity are therefore not the same property.

25
Compared with most covalent compounds, ionic compounds generally have:
  • (A) lower melting and boiling points.
  • (B) higher melting and boiling points.
  • (C) no melting point.
  • (D) identical melting points.
View Detailed Answer

Correct option: (B).

Oppositely charged ions in an ionic crystal experience strong electrostatic attractions. Considerable energy is required to overcome these forces, so ionic compounds generally have high melting and boiling points.

26
Find the molecular mass of HNO3. Given H = 1 u, N = 14 u, O = 16 u.
  • (A) 47 u
  • (B) 62 u
  • (C) 63 u
  • (D) 79 u
View Detailed Answer

Correct option: (C) 63 u.

Molecular mass = 1 + 14 + (3 × 16) = 63 u
27
Molecular mass of CH4 is: C = 12 u, H = 1 u.
  • (A) 13 u
  • (B) 14 u
  • (C) 16 u
  • (D) 48 u
View Detailed Answer

Correct option: (C) 16 u.

12 + (4 × 1) = 16 u
28
Formula unit mass of Mg(OH)2 is: Mg = 24 u, O = 16 u, H = 1 u.
  • (A) 41 u
  • (B) 42 u
  • (C) 58 u
  • (D) 82 u
View Detailed Answer

Correct option: (C) 58 u.

24 + 2(16 + 1) = 24 + 34 = 58 u
29
A species contains 11 protons and 10 electrons. It is:
  • (A) Na atom
  • (B) Na+
  • (C) Ne atom
  • (D) Cl
View Detailed Answer

Correct option: (B) Na+.

Eleven protons identify the element as sodium because atomic number = number of protons = 11. The species has one fewer electron than protons, so its charge is +1.

30
Element A has electronic configuration 2,8,1 and element B has 2,6. What is the most likely formula and bond type of the compound formed?
HOTS Olympiad Style
  • (A) AB, covalent
  • (B) A2B, ionic
  • (C) AB2, ionic
  • (D) A2B, covalent
View Detailed Answer

Correct option: (B) A2B, ionic.

A has one valence electron and tends to lose it, forming A+. B has six valence electrons and tends to gain two, forming B2−. Two A+ ions are therefore required for every B2− ion.

2A+ + B2− → A2B

Section B – 15 Two-Mark Questions

Short-answer questions testing concepts, reasoning and brief calculations.

1
Why are the initial and final masses different when vinegar and baking soda react in an open flask, but nearly the same when a balloon seals the flask?
View Detailed Answer
  1. The reaction produces carbon dioxide gas.
  2. In the open flask, CO2 escapes and is not included in the final mass. In the closed arrangement, the balloon traps the gas, so the mass of the complete system remains constant.

Thus, the observations support the Law of Conservation of Mass.

2
Why does the Law of Constant Proportions apply to compounds but not to mixtures?
View Detailed Answer

In a compound, constituent elements are chemically combined in a definite fixed ratio by mass. A mixture is formed by physically combining substances, and its components may generally be present in variable proportions. Therefore the definite-proportion law is characteristic of compounds, not mixtures.

3
How did the laws of conservation of mass and constant proportions support Dalton’s Atomic Theory?
View Detailed Answer
  • Conservation of mass is explained by atoms being rearranged rather than created or destroyed during a chemical reaction.
  • Constant proportions are explained by atoms of elements combining in fixed simple whole-number ratios to form a given compound.
4
Distinguish between an atom and an ion.
View Detailed Answer

An atom is electrically neutral because it contains equal numbers of protons and electrons. An ion is charged because an atom or group of atoms has lost or gained electrons. Loss produces a cation, while gain produces an anion.

5
Explain the formation of the HCl molecule.
View Detailed Answer

Hydrogen has one valence electron and needs one more for a duplet. Chlorine has seven valence electrons and needs one more for an octet. Each contributes one electron to one shared pair.

H + Cl → H—Cl

Hence HCl contains a single covalent bond.

6
Why is the bond in O2 represented by O=O instead of O—O?
View Detailed Answer

Each oxygen atom has six valence electrons and requires two more to complete an octet. Each oxygen therefore shares two electrons with the other, producing two shared electron pairs. Two shared pairs constitute a double bond, represented as O=O.

7
Differentiate between a cation and an anion with one example each.
View Detailed Answer
  • Cation: Positively charged ion formed by loss of electron(s), e.g. Na+.
  • Anion: Negatively charged ion formed by gain of electron(s), e.g. Cl.
8
Explain briefly how NaCl is formed by electron transfer.
View Detailed Answer

Sodium, with configuration 2,8,1, loses one electron to form Na+. Chlorine, with configuration 2,8,7, accepts this electron to form Cl. Electrostatic attraction between the oppositely charged ions forms an ionic bond.

9
Why is “formula unit” more appropriate than “molecule” for sodium chloride?
View Detailed Answer

Sodium chloride forms a continuous three-dimensional lattice of Na+ and Cl ions rather than separate NaCl molecules. NaCl therefore represents the simplest whole-number ratio, 1:1, of sodium and chloride ions and is called a formula unit.

10
State two rules used while naming binary covalent compounds.
View Detailed Answer
  • The first element retains its normal name; the second generally ends in -ide.
  • Prefixes such as mono-, di-, tri-, tetra-, penta- and hexa- indicate the number of atoms. Mono- is generally omitted for the first element.
11
Why is magnesium oxide written MgO and not Mg2O2?
View Detailed Answer

Magnesium forms Mg2+ and oxygen forms O2−. Direct criss-crossing gives Mg2O2, but an ionic formula must represent the simplest whole-number ratio. Dividing both subscripts by 2 gives MgO.

12
Explain why Al(OH)3 is correct but AlOH3 is not.
View Detailed Answer

OH is one complete polyatomic hydroxide ion. Three hydroxide ions are needed to balance Al3+. Brackets show that the subscript 3 applies to the entire OH group: Al(OH)3. AlOH3 would incorrectly suggest one oxygen and three separate hydrogen atoms.

13
Why does an ionic compound conduct electricity when molten or dissolved in water but not normally in the solid state?
View Detailed Answer

In a solid ionic crystal, ions occupy fixed positions and cannot move through the lattice. On melting or dissolving in water, the ions become mobile. These moving charged particles carry electric current.

14
Calculate the formula unit mass of KCl. K = 39 u, Cl = 35.5 u.
View Detailed Answer
Formula unit mass of KCl = 39 + 35.5 = 74.5 u

Answer: 74.5 u.

15
Mention any two applications of nuclear energy described in the chapter.
View Detailed Answer

Any two suitable applications include:

  • Generation of electricity in nuclear power plants.
  • Medicine.
  • Scientific research.
  • Space exploration.

The chapter also highlights Raja Ramanna’s contribution to India’s nuclear energy programme and its peaceful development.

Section C – 20 Three-Mark Questions

Application, experiment design, bonding, formula writing and numerical reasoning.

1
Design an experiment using zinc and dilute hydrochloric acid to demonstrate conservation of mass.
View Detailed Answer
  1. Place dilute HCl in a conical flask and zinc separately in a balloon or another compartment attached to the flask without mixing them initially.
  2. Seal the system and record its total initial mass. Allow zinc to react with HCl while ensuring the produced hydrogen gas cannot escape.
  3. After the reaction is complete, weigh the entire closed system again. The final mass should equal the initial mass within experimental uncertainty.

This demonstrates that mass is conserved even though a gas is produced.

2
5.3 g sodium carbonate reacts with 6.0 g acetic acid. Products formed are 2.2 g CO2, 0.9 g water and 8.2 g sodium acetate. Verify conservation of mass.
View Detailed Answer
Mass of reactants = 5.3 + 6.0 = 11.3 g
Mass of products = 2.2 + 0.9 + 8.2 = 11.3 g

Since total mass of reactants = total mass of products = 11.3 g, the reaction obeys the Law of Conservation of Mass.

3
A compound contains sulfur and oxygen in the mass ratio 2:3. If a sample contains 28 g sulfur, calculate the mass of oxygen and total mass of compound.
View Detailed Answer

S : O = 2 : 3

Oxygen = (3/2) × 28 = 42 g
Total mass = 28 + 42 = 70 g

The fixed 2:3 ratio illustrates the Law of Constant Proportions.

4
Student X prepares copper oxide using Cu:O = 4:1 while Y uses Cu:O = 8:2. Do their observations agree with the Law of Constant Proportions?
View Detailed Answer

Yes. X obtains a ratio of 4:1. For Y:

8 : 2 = 4 : 1

Both ratios reduce to the same value. Therefore both samples have the same composition by mass, supporting the Law of Constant Proportions.

5
State any three important postulates of Dalton’s Atomic Theory.
View Detailed Answer

Any three:

  • All matter consists of very small particles called atoms.
  • Atoms cannot be created or destroyed during a chemical reaction.
  • Atoms of a given element are identical in mass and chemical properties according to Dalton’s original theory.
  • Atoms of different elements have different masses and chemical properties.
  • Atoms combine in simple whole-number ratios to form compounds.
  • The relative numbers and kinds of atoms remain constant in a particular compound.
6
Explain the formation of N2 using the octet concept.
View Detailed Answer
  • Nitrogen has atomic number 7 and electronic configuration 2,5.
  • Each nitrogen atom needs three more electrons for an octet.
  • Two nitrogen atoms share three pairs of electrons, producing a triple covalent bond.
N≡N
7
Fluorine has atomic number 9. Explain the formation of F2.
View Detailed Answer
  • Electronic configuration of F = 2,7.
  • Each fluorine atom needs one electron to complete its octet.
  • Two fluorine atoms share one electron each, producing one shared electron pair and therefore a single covalent bond.
F—F
8
Explain covalent bond formation in water.
View Detailed Answer
  • Oxygen has six valence electrons and requires two more.
  • Each hydrogen atom has one electron and needs one more for a duplet.
  • Oxygen shares one electron pair with each of two hydrogen atoms, forming two O—H single covalent bonds.
H—O—H   =   H2O
9
Carbon has four valence electrons and oxygen has six. Explain why carbon dioxide is represented as CO2 and show its bonding.
View Detailed Answer

Carbon requires four electrons to complete its octet while each oxygen requires two. Carbon therefore shares two pairs of electrons with each of two oxygen atoms.

O=C=O

Thus one carbon atom combines with two oxygen atoms, giving CO2 with two double covalent bonds.

10
Using valencies, obtain the formulae of hydrogen sulfide, ammonia and carbon tetrachloride.
View Detailed Answer
  • H valency 1, S valency 2 → H2S.
  • N valency 3, H valency 1 → NH3.
  • C valency 4, Cl valency 1 → CCl4.

The valencies are crossed over as subscripts and reduced where required.

11
Give the systematic names of CO, CO2, CS2, PCl3, SF6 and N2O5.
View Detailed Answer
  • CO – carbon monoxide
  • CO2 – carbon dioxide
  • CS2 – carbon disulfide
  • PCl3 – phosphorus trichloride
  • SF6 – sulfur hexafluoride
  • N2O5 – dinitrogen pentoxide
12
Explain how calcium chloride is formed and why its formula is CaCl2.
View Detailed Answer

Calcium loses two valence electrons to form Ca2+. Each chlorine atom accepts one electron to form Cl. Therefore two chloride ions are necessary to balance the +2 charge of one calcium ion.

Ca2+ + 2Cl → CaCl2
13
Predict the ions formed by potassium and calcium and write the formula of each chloride.
View Detailed Answer
  • Potassium loses one electron → K+. It combines 1:1 with Cl → KCl.
  • Calcium loses two electrons → Ca2+. It requires two Cl ions → CaCl2.
14
Explain the formation of sodium sulfide, Na2S.
View Detailed Answer

Each sodium atom loses one electron and forms Na+. Sulfur needs two electrons and forms S2−. Therefore two sodium atoms provide the two electrons required by one sulfur atom.

2Na+ + S2− → Na2S
15
Give the formula and valency/charge of hydroxide, nitrate, carbonate, sulfate and ammonium ions.
View Detailed Answer
IonFormulaValency / Charge magnitude
HydroxideOH1
NitrateNO31
CarbonateCO32−2
SulfateSO42−2
AmmoniumNH4+1
16
Write formulae for compounds formed by: (i) Fe3+ and OH, (ii) K+ and CO32−, (iii) Al3+ and SO42−.
View Detailed Answer
  • Fe3+ + OH → Fe(OH)3
  • K+ + CO32− → K2CO3
  • Al3+ + SO42− → Al2(SO4)3

In each case, the total positive and negative charges in the compound are equal.

17
State three general differences between ionic and covalent compounds based on solubility, conductivity and melting/boiling points.
View Detailed Answer
PropertyIonicCovalent
SolubilityGenerally soluble in waterMany are insoluble in water but may dissolve in petrol/kerosene
ConductivityConduct when molten or in aqueous solutionGenerally poor conductors
Melting/boiling pointGenerally highUsually comparatively low
18
In an experiment, sodium chloride, copper sulfate, sugar, camphor and naphthalene are tested in water. Predict the broad conductivity pattern and explain it.
View Detailed Answer
  • NaCl and copper sulfate form mobile ions in aqueous solution, so their solutions conduct electricity.
  • Sugar may dissolve but does not produce ions, so its solution does not conduct appreciably.
  • Camphor and naphthalene are covalent substances and are generally insoluble in water and non-conducting.

Therefore conductivity depends on the presence of mobile charged particles, not simply on whether a substance appears to dissolve.

19
Calculate the formula unit mass of Ca(NO3)2. Ca = 40 u, N = 14 u, O = 16 u.
View Detailed Answer
Ca(NO3)2 = 40 + 2[14 + 3(16)]
= 40 + 2(14 + 48) = 40 + 124 = 164 u

Formula unit mass = 164 u.

20
Determine electrons and neutrons in 27Al, 80Br and 201Hg2+. Their proton numbers are 13, 35 and 80 respectively.
Olympiad Style
View Detailed Answer
Species Protons Electrons Neutrons
27Al 13 13 27 − 13 = 14
80Br 35 36 80 − 35 = 45
201Hg2+ 80 78 201 − 80 = 121

Negative charge means electron gain; positive charge means electron loss. Ion formation does not alter the number of neutrons.

Section D – 15 Four-Mark Questions

Long-answer, competency, experimental and higher-order reasoning questions.

1
Describe the two vinegar–baking soda experimental arrangements used to investigate conservation of mass and explain their different observations.
View Detailed Answer
  1. Open arrangement: Vinegar is placed in a flask and baking soda is added. Brisk effervescence occurs as CO2 forms.
  2. The gas escapes into the surroundings, so the measured final mass of the apparatus may be smaller than the initial mass.
  3. Closed arrangement: Baking soda is placed in a balloon attached securely to the flask containing vinegar. The system is weighed before mixing.
  4. When the substances react, CO2 inflates the balloon but cannot escape. The total final mass remains equal to the initial mass within experimental error.

The experiment shows that an apparent loss in an open system results from matter leaving the measured system, not from destruction of matter.

2
Explain how sodium sulfate and barium chloride solutions may be used to verify the Law of Conservation of Mass. Mention an important precaution.
View Detailed Answer
  1. Keep sodium sulfate solution in flask A and barium chloride solution in flask B and record the combined mass.
  2. Transfer one solution into the other. A white precipitate of barium sulfate forms along with sodium chloride.
  3. Place both flasks back on the balance. The total mass remains essentially unchanged, demonstrating conservation of mass.
  4. Precaution: Both flasks should remain part of the weighing before and after transfer because traces of solution may remain stuck to the flask walls.
Sodium sulfate + Barium chloride → Barium sulfate + Sodium chloride
3
Explain both major laws of chemical combination covered in the chapter using one numerical illustration for each.
View Detailed Answer

1. Law of Conservation of Mass:

Total mass before a chemical reaction equals total mass after the reaction. Example: if reactants have masses 4.0 g and 2.92 g:

Total reactants = 6.92 g

If products are 1.76 g, 0.72 g and 4.44 g:

Total products = 1.76 + 0.72 + 4.44 = 6.92 g

2. Law of Constant Proportions:

A given compound always contains its constituent elements in a fixed ratio by mass. In water H:O = 1:8. Thus 18 g water contains:

Hydrogen = 2 g; Oxygen = 16 g
4
Suppose atoms of the same two elements could combine in completely arbitrary proportions to make what was claimed to be the same compound. What difficulty would this create for the concept of a chemical compound?
HOTS
View Detailed Answer
  • A compound would no longer possess a definite composition.
  • Samples obtained from different places could contain different mass ratios of their elements.
  • The Law of Constant Proportions would not hold for that substance.
  • Reliable chemical formulae representing definite numbers or ratios of atoms would lose their meaning for the supposed compound.

Fixed composition is therefore one of the key characteristics that distinguish a pure compound from a variable mixture.

5
Compare bonding in H2, Cl2, O2, N2 and HCl in terms of electrons required and number of shared pairs.
View Detailed Answer
MoleculeNeed of each atomShared pairsRepresentation
H2Each H needs 1 electron1H—H
Cl2Each Cl needs 1 electron1Cl—Cl
O2Each O needs 2 electrons2O=O
N2Each N needs 3 electrons3N≡N
HClH needs 1; Cl needs 11H—Cl

In every case the atoms gain greater stability through electron sharing.

6
Explain four important conventions used in naming covalent compounds and illustrate them using suitable examples.
View Detailed Answer
  1. The first element keeps its ordinary name; the second generally ends in -ide.
  2. Prefixes mono-, di-, tri-, tetra-, penta-, hexa-, etc. indicate atom numbers.
  3. Mono- is usually omitted before the first element: CO is carbon monoxide, not monocarbon monoxide.
  4. Where necessary, the final vowel of a prefix is dropped before “oxide”: N2O4 is dinitrogen tetroxide, while CO is monoxide.

Other examples: CO2 carbon dioxide, PCl3 phosphorus trichloride and SF6 sulfur hexafluoride.

7
Show by electron transfer how MgCl2 and CaO are formed. Explain why both are ionic compounds.
View Detailed Answer

Magnesium chloride:

Mg → Mg2+ + 2e
2Cl + 2e → 2Cl
Mg2+ + 2Cl → MgCl2

Calcium oxide:

Ca → Ca2+ + 2e
O + 2e → O2−
Ca2+ + O2− → CaO

Both contain oppositely charged ions held together by electrostatic attraction. This attraction constitutes the ionic bond.

8
Explain how the crystal structure of an ionic compound accounts for its high melting point and electrical conductivity behaviour.
View Detailed Answer
  • Ionic compounds consist of a regular three-dimensional arrangement of oppositely charged ions.
  • Strong electrostatic attractions hold the ions together, so a large amount of energy is required to separate them. This gives generally high melting and boiling points.
  • In the solid state, ions are fixed in position and cannot carry current.
  • When molten or dissolved, ions become mobile and can carry electric charge, so the substance conducts.
9
Write the formulae of magnesium hydroxide, calcium carbonate, aluminium hydroxide and aluminium sulfate. Explain the use of brackets.
View Detailed Answer
  • Magnesium hydroxide – Mg(OH)2
  • Calcium carbonate – CaCO3
  • Aluminium hydroxide – Al(OH)3
  • Aluminium sulfate – Al2(SO4)3

Brackets are used when two or more of the same polyatomic ion are required. Thus (OH)3 means three complete OH ions, and (SO4)3 means three complete sulfate ions.

10
Write formulae for ferric chloride, cuprous oxide, aluminium nitrate and ammonium sulfate, showing charge balance.
View Detailed Answer
CompoundIonsFormula
Ferric chlorideFe3+, ClFeCl3
Cuprous oxideCu+, O2−Cu2O
Aluminium nitrateAl3+, NO3Al(NO3)3
Ammonium sulfateNH4+, SO42−(NH4)2SO4
11
A student is given NaCl, CuSO4, sugar, camphor and naphthalene. Explain how solubility and conductivity tests can help classify them broadly as ionic or covalent.
View Detailed Answer
  1. Test each substance for solubility in water and in non-aqueous solvents such as petrol/kerosene using appropriate safety precautions.
  2. NaCl and CuSO4 are ionic examples and are generally water-soluble.
  3. Their aqueous solutions conduct because mobile ions are present.
  4. Camphor and naphthalene are covalent and generally dissolve better in non-aqueous solvents; sugar is a useful exception because it dissolves in water but does not ionise and therefore does not conduct.

Thus multiple properties must be considered rather than using water-solubility alone.

12
Carbon and oxygen combine in the mass ratio 3:8 to form carbon dioxide. Find (i) oxygen required for 7.5 g carbon, (ii) CO2 produced, and (iii) CO2 produced from 15 g carbon.
View Detailed Answer

For C:O = 3:8:

Oxygen for 7.5 g C = 7.5 × 8/3 = 20 g
CO2 produced = 7.5 + 20 = 27.5 g
For 15 g C, oxygen = 15 × 8/3 = 40 g
CO2 = 15 + 40 = 55 g

The calculation applies both constant composition and conservation of mass.

13
Calculate: (i) molecular mass of H2O, (ii) molecular mass of CO2, (iii) formula unit mass of Na2O, and (iv) formula unit mass of Mg(OH)2. Use H=1, C=12, O=16, Na=23, Mg=24.
View Detailed Answer
  • H2O = 2(1) + 16 = 18 u
  • CO2 = 12 + 2(16) = 44 u
  • Na2O = 2(23) + 16 = 62 u
  • Mg(OH)2 = 24 + 2(16 + 1) = 58 u
14
A species has 11 protons, 12 neutrons and 10 electrons. Determine its atomic number, mass number, charge, electronic configuration and identity.
View Detailed Answer
  • Atomic number = number of protons = 11.
  • Mass number = protons + neutrons = 11 + 12 = 23.
  • It has 11 protons but only 10 electrons, so charge = +1.
  • Electronic configuration for 10 electrons = 2,8.
  • Atomic number 11 corresponds to sodium, so the species is 23Na+.
15
Elements A and B have configurations A = 2,8,5 and B = 2,8,7. Predict their bonding behaviour, likely bond type and simplest formula when they combine.
HOTS Olympiad Style
View Detailed Answer
  • A has five valence electrons and requires three more to complete an octet.
  • B has seven valence electrons and requires one more.
  • Both have more than four valence electrons, so electron sharing is expected rather than one readily donating several electrons to the other.
  • A can share with three B atoms. The simplest formula is therefore AB3, with covalent bonding.

Section E – 5 Competency-Based Case Studies

Integrated questions requiring interpretation, calculation and scientific reasoning.

Case Study 1 – The Inflating Balloon Experiment

Law of Conservation of Mass • Experimental Reasoning
A group of students places vinegar in a conical flask and baking soda in a balloon. The balloon is fixed tightly over the mouth of the flask. The complete apparatus is weighed. The balloon is then lifted so that the baking soda falls into the vinegar. Vigorous effervescence occurs and the balloon inflates. The apparatus is weighed again.

(a) Name the gas responsible for inflating the balloon.

(b) Why should the final mass be approximately equal to the initial mass?

(c) What would happen to the measured mass if the reaction were performed in an open beaker?

(d) State the scientific law demonstrated.

(e) Why should the balloon and flask both remain part of the system during weighing?

View Detailed Case Study Solution

(a) Carbon dioxide, CO2.

(b) The balloon traps the gas. Since no significant matter leaves the closed system, all reactant and product matter remains on the balance. Hence initial and final masses should be equal within experimental uncertainty.

(c) The measured final mass would appear smaller because carbon dioxide would escape into the surroundings.

(d) Law of Conservation of Mass: matter can neither be created nor destroyed in a chemical reaction.

(e) Traces of material may remain in or on the balloon. Removing any component would change what is being weighed and could introduce experimental error.

Case Study 2 – Is Water Always the Same?

Law of Constant Proportions • Numerical Application
Samples of water are collected from a river, a borewell and the sea. After suitable purification, each sample is analysed. In every case, hydrogen and oxygen are found to occur in the mass ratio 1:8.

(a) Which law is illustrated?

(b) How much oxygen is present with 3 g hydrogen?

(c) What mass of water contains 5 g hydrogen?

(d) If a sample claimed to be pure water contains hydrogen and oxygen in a 1:6 ratio, what conclusion can be drawn?

(e) Why does source not affect the composition of purified water?

View Detailed Case Study Solution

(a) Law of Constant Proportions or Law of Definite Proportions.

(b)

H:O = 1:8
For 3 g H, oxygen = 3 × 8 = 24 g.

(c)

Oxygen with 5 g H = 40 g
Mass of water = 5 + 40 = 45 g.

(d) A 1:6 H:O ratio does not correspond to the fixed composition of pure water. The sample, measurement or identification would therefore require investigation.

(e) Pure water is a definite chemical compound. Its constituent elements occur in a fixed ratio by mass irrespective of its geographical source.

Case Study 3 – Which Solution Lights the Bulb?

Ionic & Covalent Compounds • Conductivity • Solubility
A student uses a 9 V battery, bulb and two electrodes to test aqueous solutions of sodium chloride, copper sulfate and sugar. The bulb glows with sodium chloride and copper sulfate solutions but not with sugar solution.

(a) Why do NaCl and CuSO4 solutions conduct electricity?

(b) Why does sugar solution fail to conduct even though sugar dissolves?

(c) Would solid NaCl conduct? Explain.

(d) Predict whether molten NaCl conducts electricity.

(e) Name one important safety precaution for the experiment.

View Detailed Case Study Solution

(a) These ionic compounds provide mobile ions in aqueous solution. The ions carry electric charge through the liquid.

(b) Sugar is covalent. Although it can dissolve, it does not produce the freely moving ions needed to conduct electric current.

(c) No. In solid NaCl, Na+ and Cl ions are held in fixed positions in a crystal lattice and cannot migrate.

(d) Yes. On melting, the ions become mobile and can carry current.

(e) Use a low-voltage battery and do not touch connected electrodes. Petrol and kerosene, if used during solubility tests, must also be handled away from flames because they are flammable.

Case Study 4 – Building Ionic Compounds

Valency • Polyatomic Ions • Formula Writing
A chemistry card game contains the ions Al3+, Mg2+, NH4+, Cl, OH, CO32− and SO42−. Students must combine cards so that each compound has zero net electrical charge.

(a) Write the formula formed from Al3+ and Cl.

(b) Write the formula formed from Mg2+ and OH.

(c) Write the formula formed from NH4+ and SO42−.

(d) Why are brackets required in two of the answers above?

(e) Why are ionic formulae written in the simplest whole-number ratio?

View Detailed Case Study Solution

(a) AlCl3.

(b) Mg(OH)2.

(c) (NH4)2SO4.

(d) OH and NH4+ are polyatomic ions. When more than one complete polyatomic ion is required, brackets ensure that the subscript applies to the whole ion rather than just its final element.

(e) Ionic compounds form extended crystal structures rather than separate molecules. Their formula indicates the simplest whole-number ratio of oppositely charged ions needed for overall electrical neutrality.

Case Study 5 – Mystery Elements A and B

Electronic Configuration • Bonding • HOTS
Element A has electronic configuration 2,8,2, while element B has electronic configuration 2,7. Students are asked to predict the compound formed between them without being told their names.

(a) How many electrons will A tend to lose?

(b) What charge will A acquire?

(c) How many electrons will each B atom tend to gain?

(d) Predict the formula of the compound.

(e) Predict its bonding type and two likely general properties.

View Detailed Case Study Solution

(a) A has two valence electrons and tends to lose both to achieve a stable configuration.

(b) It forms A2+.

(c) Each B atom has seven valence electrons and gains one electron, forming B.

(d) Two B ions are required to balance one A2+ ion:

A2+ + 2B → AB2

(e) Electron transfer produces an ionic compound. It would generally be expected to have a comparatively high melting point and conduct electricity when molten or when its ions are mobile in aqueous solution. In its solid state, the ions would remain fixed and it would not normally conduct electricity.

Final Challenge – Mixed Revision

A compound X does not conduct electricity as a solid, has a high melting point, and conducts when molten. Another compound Y has a relatively low melting point and does not conduct electricity even when dissolved in water. Identify the most probable bonding type in X and Y and justify your answer.
HOTS Olympiad Style
View Detailed Answer

X is most likely ionic.

  • Strong electrostatic attractions explain its high melting point.
  • Ions are fixed in the solid state, so the solid does not conduct.
  • When molten, the ions become mobile and conduct electricity.

Y is most likely covalent.

  • Many covalent compounds have relatively low melting and boiling points.
  • They generally do not provide mobile ions and therefore usually do not conduct electricity.

High-Yield Revision Points

  • Conservation of mass: total mass of reactants = total mass of products.
  • Constant proportions: a given compound contains its elements in a fixed mass ratio.
  • Covalent bond: formed by sharing electron pairs.
  • Ionic bond: electrostatic attraction between oppositely charged ions formed after electron transfer.
  • Cation: positive ion; anion: negative ion.
  • Ionic compounds form extended crystal structures rather than independent molecules.
  • Solid ionic compounds generally do not conduct because ions are fixed.
  • Molten or dissolved ionic compounds conduct because their ions can move.
  • Covalent substances generally do not provide mobile ions.
  • Use brackets when more than one of the same polyatomic ion occurs in a formula.
  • Always reduce ionic formulae to the simplest whole-number ratio.
  • Molecular mass is used for molecules; formula unit mass is used for ionic formula units.

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