SK TUITIONS • CLASS 9 CBSE SCIENCE

Cell: The Building Block of Life – Complete Question Bank

NCERT • Competency Based • Exemplar Style • HOTS • Olympiad Practice

Complete chapter coverage with progressively difficult questions and detailed answers.

30MCQs
152 Markers
203 Markers
154 Markers
5Case Studies
25Olympiad

Complete Chapter Coverage

Cell as Structural & Functional Unit
Unicellular & Multicellular Life
Robert Hooke & Microscopy
Resolution, Contrast & Magnification
Cell-size Numericals
Light & Electron Microscopes
Cell Membrane
Fluid-Mosaic Model
Diffusion & Osmosis
Isotonic, Hypotonic & Hypertonic Solutions
Cell Wall & Cellulose
Plant vs Animal Cells
Prokaryotic vs Eukaryotic Cells
Cytoplasm & Cytoskeleton
Nucleus, Chromatin & Chromosomes
DNA & Genes
Ribosomes
RER & SER
Golgi Apparatus
Lysosomes
Mitochondria & ATP
Plastids
Chloroplasts, Chromoplasts & Leucoplasts
Vacuoles
Synthetic DNA Experiment
Cell Division
Mitosis & Meiosis
Cell Culture
Cell Theory
Contact Inhibition & Cancer
Programmed Cell Death
Totipotency

Section A – 30 Multiple Choice Questions

Questions progress from fundamental NCERT concepts to application-based reasoning.

1
The basic structural and functional unit of a living organism is:
  • (A) Tissue
  • (B) Cell
  • (C) Organ
  • (D) Organ system
View Detailed Answer

Correct option: (B) Cell.

The cell is the lowest level of biological organisation at which the essential characteristics of life are expressed. Tissues, organs and organ systems are formed through organisation of cells.

2
Robert Hooke first observed cells in cork in:
  • (A) 1590
  • (B) 1665
  • (C) 1838
  • (D) 1855
View Detailed Answer

Correct option: (B) 1665.

Hooke examined a thin slice of cork using his self-designed microscope and observed small box-like compartments. He called these compartments “cells”.

3
The approximate limit of resolution of the unaided human eye at about 25 cm is:
  • (A) 1 cm
  • (B) 1 mm
  • (C) 0.1 mm
  • (D) 0.1 µm
View Detailed Answer

Correct option: (C) 0.1 mm.

Two points separated by about 0.1 mm can normally be distinguished by the eye at its near point. At smaller separations they appear as one point.

4
A microscope has a 10X eyepiece and a 40X objective lens. Its total magnification is:
  • (A) 50X
  • (B) 400X
  • (C) 4X
  • (D) 4000X
View Detailed Answer

Correct option: (B) 400X.

Total magnification = Eyepiece magnification × Objective magnification = 10 × 40 = 400X
5
The diameter of a microscope field is 4 mm and 20 cells lie across it. Estimated cell size is:
  • (A) 20 µm
  • (B) 50 µm
  • (C) 200 µm
  • (D) 800 µm
View Detailed Answer

Correct option: (C) 200 µm.

4 mm = 4000 µm
Cell size = 4000 ÷ 20 = 200 µm
6
Electron microscopes can reveal finer cellular details mainly because they:
  • (A) use sunlight.
  • (B) use a beam of electrons.
  • (C) use only one lens.
  • (D) make cells larger permanently.
View Detailed Answer

Correct option: (B).

An electron microscope uses a beam of electrons rather than visible light and can reveal structures at the nanometre scale with much greater detail.

7
The plasma membrane is described as selectively permeable because it:
  • (A) allows every substance to cross.
  • (B) blocks every substance.
  • (C) allows some substances while restricting others.
  • (D) occurs only in plant cells.
View Detailed Answer

Correct option: (C).

The cell membrane controls exchange between the cell and its surroundings by permitting certain substances to pass while restricting others.

8
Osmosis is best defined as:
  • (A) movement of any particles without a membrane.
  • (B) diffusion of water across a selectively permeable membrane.
  • (C) movement of solute from low to high concentration.
  • (D) transport occurring only in plants.
View Detailed Answer

Correct option: (B).

Osmosis specifically involves movement of water through a selectively permeable membrane from a region with more water and less solute towards one with less water and more solute.

9
A potato piece placed in plain water usually gains mass because:
  • (A) salt enters the potato.
  • (B) water enters its cells by osmosis.
  • (C) starch leaves its cells.
  • (D) cellulose is produced.
View Detailed Answer

Correct option: (B).

Plain water is relatively dilute compared with the cell contents. Water therefore moves into the potato cells across their selectively permeable membranes.

10
An animal cell placed in a concentrated salt solution will most likely:
  • (A) swell.
  • (B) remain unchanged.
  • (C) lose water and shrink.
  • (D) develop a cell wall.
View Detailed Answer

Correct option: (C).

The surrounding solution is hypertonic. Water moves from the cell into the more concentrated external solution, causing the animal cell to shrink.

11
Which arrangement correctly represents the cell membrane?
  • (A) Cellulose wall with DNA embedded in it
  • (B) Lipid bilayer containing proteins
  • (C) Protein bilayer without lipids
  • (D) Starch layer with chlorophyll
View Detailed Answer

Correct option: (B).

The fluid-mosaic model describes the plasma membrane as a lipid bilayer containing embedded proteins. Its components can move within the membrane, making it fluid.

12
The principal structural material of the plant cell wall described in the chapter is:
  • (A) Glycogen
  • (B) Cellulose
  • (C) DNA
  • (D) ATP
View Detailed Answer

Correct option: (B) Cellulose.

Cellulose is a carbohydrate made of many linked glucose units. It contributes rigidity and mechanical support to plant cell walls.

13
Which structure occurs in bacterial, plant and animal cells?
  • (A) Membrane-bound nucleus
  • (B) Chloroplast
  • (C) Cell membrane
  • (D) Large central vacuole
View Detailed Answer

Correct option: (C) Cell membrane.

The plasma membrane is a universal cellular feature. Bacteria lack a membrane-bound nucleus and many membrane-bound organelles, while chloroplasts and large central vacuoles are characteristic of plant cells.

14
The genetic material of a typical prokaryotic cell occurs mainly in the:
  • (A) nucleolus.
  • (B) nucleoid.
  • (C) Golgi apparatus.
  • (D) lysosome.
View Detailed Answer

Correct option: (B) Nucleoid.

Prokaryotic cells do not have a membrane-bound nucleus. Their genetic material lies in a cytoplasmic region termed the nucleoid.

15
Which feature most directly distinguishes a typical eukaryotic cell from a prokaryotic cell?
  • (A) Presence of cytoplasm
  • (B) Presence of genetic material
  • (C) Membrane-bound nucleus and organelles
  • (D) Presence of a cell membrane
View Detailed Answer

Correct option: (C).

Eukaryotic cells possess a well-defined membrane-bound nucleus and several membrane-bound organelles. These are absent from prokaryotic cells.

16
The dense body inside the nucleus where ribosomal subunits are synthesised is the:
  • (A) nucleoid.
  • (B) nucleolus.
  • (C) lysosome.
  • (D) vacuole.
View Detailed Answer

Correct option: (B) Nucleolus.

Ribosomal subunits are produced in the nucleolus and later move into the cytoplasm, where they assemble to form functional ribosomes.

17
In a non-dividing eukaryotic cell, DNA occurs mainly as:
  • (A) chromatin material.
  • (B) cristae.
  • (C) cell sap.
  • (D) lysosomal enzymes.
View Detailed Answer

Correct option: (A).

In non-dividing cells, DNA and associated proteins are present as thread-like chromatin. Before cell division, this material becomes organised into visible chromosomes.

18
Ribosomes are primarily responsible for:
  • (A) protein synthesis.
  • (B) ATP storage.
  • (C) photosynthesis.
  • (D) chromosome separation.
View Detailed Answer

Correct option: (A).

Ribosomes are the sites at which proteins are synthesised. They may occur freely in the cytoplasm or attached to rough ER.

19
Rough endoplasmic reticulum appears rough because:
  • (A) DNA is attached to it.
  • (B) ribosomes occur on its surface.
  • (C) it contains cellulose.
  • (D) its membrane is folded into cristae.
View Detailed Answer

Correct option: (B).

Numerous ribosomes are attached to the surface of RER, giving it a rough appearance under an electron microscope and linking it strongly with protein synthesis and secretion.

20
A cell specialised for synthesis of large amounts of fats would be expected to contain abundant:
  • (A) SER.
  • (B) cell wall.
  • (C) nucleoid.
  • (D) chromoplast.
View Detailed Answer

Correct option: (A) Smooth ER.

SER lacks ribosomes and is involved in the synthesis and storage of fats and certain hormones.

21
Which organelle modifies, sorts and packages proteins and lipids?
  • (A) Golgi apparatus
  • (B) Nucleolus
  • (C) Mitochondrion
  • (D) Chromoplast
View Detailed Answer

Correct option: (A).

The Golgi apparatus receives cellular products, modifies and sorts them, and packages them into vesicles for transport, secretion or formation of structures such as lysosomes.

22
Lysosomes contain enzymes mainly involved in:
  • (A) intracellular breakdown.
  • (B) photosynthesis.
  • (C) chromosome formation.
  • (D) cellulose synthesis.
View Detailed Answer

Correct option: (A).

Lysosomal enzymes break down unwanted materials and damaged cellular components. Breakdown products can subsequently be released into the cytoplasm and reused.

23
The folds of the inner mitochondrial membrane are called:
  • (A) chromatin.
  • (B) cristae.
  • (C) stroma.
  • (D) nucleoli.
View Detailed Answer

Correct option: (B) Cristae.

Cristae greatly increase the surface area of the mitochondrial inner membrane for chemical reactions associated with cellular energy production.

24
ATP is described in the chapter as the:
  • (A) genetic material.
  • (B) energy currency of the cell.
  • (C) main cell-wall component.
  • (D) pigment of chloroplasts.
View Detailed Answer

Correct option: (B).

Energy released during cellular respiration is stored in ATP and subsequently used to support many cellular activities.

25
The plastid mainly associated with storing starch, oils or proteins is:
  • (A) chloroplast.
  • (B) chromoplast.
  • (C) leucoplast.
  • (D) lysosome.
View Detailed Answer

Correct option: (C) Leucoplast.

Leucoplasts are colourless plastids specialised for food storage. Some leucoplasts in potato and Colocasia cells store starch.

26
A mature plant cell remains firm partly because its large central vacuole:
  • (A) produces chromosomes.
  • (B) maintains pressure by storing water.
  • (C) forms ribosomes.
  • (D) digests cellulose.
View Detailed Answer

Correct option: (B).

The large central vacuole contains cell sap. Accumulated water helps maintain internal pressure, contributing to firmness of the plant cell.

27
Mitosis normally produces:
  • (A) four genetically different daughter cells.
  • (B) two genetically identical daughter cells.
  • (C) one daughter cell.
  • (D) four cells with double chromosome number.
View Detailed Answer

Correct option: (B).

Mitosis produces two daughter cells that receive essentially the same DNA and chromosome number as the parent cell. It is important for growth, repair and maintenance.

28
Meiosis produces:
  • (A) two identical cells with unchanged chromosome number.
  • (B) four cells with half the chromosome number.
  • (C) eight body cells.
  • (D) one gamete with double the DNA.
View Detailed Answer

Correct option: (B).

Meiosis involves two divisions and produces four daughter cells. Each receives half the chromosome number of the parent cell, making meiosis important in gamete formation.

29
“All cells arise from pre-existing cells” is chiefly associated with:
  • (A) Robert Hooke
  • (B) Matthias Schleiden
  • (C) Rudolf Virchow
  • (D) Camillo Golgi
View Detailed Answer

Correct option: (C) Rudolf Virchow.

Virchow expanded Cell Theory in 1855 by stating that new cells originate only from pre-existing cells.

30
Loss of contact inhibition in an animal cell population is most directly associated with:
HOTS
  • (A) controlled tissue repair.
  • (B) uncontrolled division and tumour formation.
  • (C) formation of cell walls.
  • (D) conversion of mitosis into osmosis.
View Detailed Answer

Correct option: (B).

Normal animal cells generally stop dividing when they contact neighbouring cells. Cancer cells may lose this growth control and continue dividing, contributing to tumour formation.

Section B – 15 Two-Mark Questions

Concise conceptual and reasoning questions.

1
Why is the cell called both the structural and functional unit of life?
View Detailed Answer

Cells provide the basic physical structure of all living organisms. At the same time, essential life activities occur through cellular processes. Even in multicellular organisms, tissues and organs function because their constituent cells perform coordinated activities.

2
Differentiate between magnification and resolution.
View Detailed Answer

Magnification is the extent to which an object appears larger than its actual size. Resolution refers to clarity and the ability to distinguish two closely spaced points as separate. A large image is not necessarily useful if it has poor resolution.

3
A microscope has a 15X eyepiece and 40X objective. Calculate total magnification.
View Detailed Answer
Total magnification = 15 × 40 = 600X

Therefore, the object appears approximately 600 times larger.

4
Differentiate between diffusion and osmosis.
View Detailed Answer

Diffusion: net movement of particles from higher to lower concentration and does not necessarily require a membrane.

Osmosis: diffusion of water across a selectively permeable membrane.

5
Why does a potato piece swell in plain water but shrink in concentrated salt solution?
View Detailed Answer

In plain water, water enters potato cells by osmosis, increasing their mass and size. In concentrated salt solution, water moves out of the cells toward the more concentrated external solution, causing loss of mass and shrinkage.

6
Why can the cell wall be permeable while the plasma membrane is selectively permeable?
View Detailed Answer

The rigid cell wall allows water and some dissolved substances to pass through it relatively freely. The underlying plasma membrane regulates which substances actually enter or leave the living cell, making it selectively permeable.

7
State two major differences between prokaryotic and eukaryotic cells.
View Detailed Answer
  • Prokaryotes lack a membrane-bound nucleus; eukaryotes possess one.
  • Prokaryotes lack membrane-bound organelles; eukaryotes contain several such organelles.
8
Why do mature human RBCs lack a nucleus, and what disadvantage results?
View Detailed Answer

Absence of a nucleus leaves additional space for haemoglobin, helping the RBC transport more oxygen. However, enucleated mature RBCs cannot divide or effectively repair themselves, contributing to their limited lifespan of about 120 days.

9
Differentiate between RER and SER.
View Detailed Answer

RER has ribosomes on its surface and is strongly associated with protein synthesis and secretion. SER lacks surface ribosomes and participates in synthesis and storage of fats and certain hormones.

10
Why are lysosomes described as a cellular clean-up system?
View Detailed Answer

Lysosomes contain digestive enzymes capable of breaking down unwanted materials and damaged or worn-out cellular parts. The useful breakdown products may then return to the cytoplasm and be reused.

11
Why are cristae important in a mitochondrion?
View Detailed Answer

Cristae are folds of the inner mitochondrial membrane. They increase its surface area, providing more area for chemical reactions associated with energy production during cellular respiration.

12
Distinguish among chloroplasts, chromoplasts and leucoplasts.
View Detailed Answer
  • Chloroplasts: contain chlorophyll and participate in photosynthesis.
  • Chromoplasts: contain coloured pigments, often yellow, orange or red.
  • Leucoplasts: lack pigments and mainly store materials such as starch, oils or proteins.
13
Give two differences between mitosis and meiosis.
View Detailed Answer

Mitosis produces two genetically similar daughter cells with the same chromosome number and is important in growth and repair. Meiosis involves two divisions, produces four daughter cells with half the chromosome number and is associated with formation of gametes.

14
State any two principles of classical Cell Theory.
View Detailed Answer

Any two:

  • All living organisms consist of one or more cells.
  • The cell is the basic structural and functional unit of living organisms.
  • All cells arise from pre-existing cells.
15
What is programmed cell death and why is it useful?
View Detailed Answer

Programmed Cell Death is a genetically regulated and organised process of selective cell destruction. It contributes to normal development and cellular quality control. The chapter illustrates this with removal of cells between developing fingers.

Section C – 20 Three-Mark Questions

Application, comparison, experimental reasoning and numerical questions.

1
A microscope field measures 6 mm across. Thirty cells fit along its diameter. Calculate the estimated size of one cell in micrometres.
View Detailed Answer
6 mm = 6000 µm
Estimated cell size = 6000 ÷ 30 = 200 µm

Hence, the approximate size of one cell is 200 µm.

2
Explain the importance of resolution, magnification and contrast in microscopy.
View Detailed Answer
  • Magnification makes a small specimen appear larger.
  • Resolution determines whether nearby details can be seen distinctly.
  • Contrast makes different parts easier to distinguish by increasing differences in brightness or appearance.

Effective microscopy depends on improvement of all three rather than magnification alone.

3
Explain the potato experiment used to demonstrate osmosis.
View Detailed Answer
  1. Take roughly equal potato pieces and record their initial masses.
  2. Place one in plain water and the other in concentrated salt or sugar solution.
  3. The first gains water and swells, whereas the second loses water and shrinks.

The results show that water crosses selectively permeable cell membranes according to differences in water/solute concentration.

4
Explain what happens to an animal cell in isotonic, hypotonic and hypertonic solutions.
View Detailed Answer
  • Isotonic: external and internal solute concentrations are similar; there is no major net change in cell size.
  • Hypotonic: external solution is more dilute; water enters and the cell swells.
  • Hypertonic: external solution is more concentrated; water leaves and the cell shrinks.
5
Describe three important features of the fluid-mosaic model.
View Detailed Answer
  • The membrane contains a lipid bilayer with water-attracting heads facing outward and water-repelling tails inward.
  • Different proteins are embedded in the bilayer and may function as gatekeepers.
  • Membrane components can move sideways, rotate and otherwise shift within the membrane, producing its fluid character.
6
Explain why Rhoeo cells and cheek cells respond differently to concentrated sugar solution.
View Detailed Answer

Both cells lose water by osmosis. The inner living content of a Rhoeo cell shrinks and its membrane moves away from the wall, but the rigid cell wall preserves the overall outer shape. Cheek cells lack a cell wall, so the entire cells shrink considerably.

7
Why is the cell wall especially useful to plants that remain fixed in one place?
View Detailed Answer
  • It provides rigidity and mechanical support.
  • It helps cells retain shape and assists leaves and flowers in remaining firm.
  • It helps plants withstand environmental stresses such as wind and rain while still remaining permeable to water and some dissolved minerals.
8
Compare bacterial, plant and animal cells with respect to cell wall, nucleus and membrane-bound organelles.
View Detailed Answer
FeatureBacterialPlantAnimal
Cell wallPresentPresentAbsent
Well-defined nucleusAbsentPresentPresent
Membrane-bound organellesAbsentPresentPresent
9
Explain the relationship among DNA, genes, chromatin and chromosomes.
View Detailed Answer

DNA carries genetic information. Functional segments of DNA are called genes. In a non-dividing cell, DNA and associated proteins occur as thread-like chromatin. As the cell prepares to divide, chromatin becomes organised into distinct chromosomes.

10
Trace the path of a protein intended for secretion from its synthesis to the cell surface.
View Detailed Answer

A simplified pathway is:

Ribosome on RER → Rough ER → Transport vesicle → Golgi apparatus → Secretory vesicle → Plasma membrane

Ribosomes synthesise the protein, ER participates in its processing/transport, and Golgi modifies, sorts and packages it for secretion.

11
Compare the roles of RER, SER and Golgi apparatus.
View Detailed Answer
  • RER: ribosome-bearing; closely associated with protein synthesis and secretion.
  • SER: lacks ribosomes; involved in synthesis/storage of fats and some hormones.
  • Golgi: modifies, sorts and packages proteins and lipids into vesicles.
12
Explain the structural adaptations of mitochondria for energy production.
View Detailed Answer
  • A mitochondrion possesses two surrounding membranes.
  • The inner membrane forms numerous folds called cristae.
  • Cristae increase the available surface area for reactions involved in cellular energy production. Energy released is stored in ATP.
13
Give three similarities between mitochondria and chloroplasts mentioned or indicated in the chapter.
View Detailed Answer
  • Both are double-membrane-bound organelles.
  • Both contain their own DNA.
  • Both contain ribosomes and can make some of their own proteins.

The chapter notes that these characteristics suggest an evolutionary relationship with certain single-celled organisms.

14
Why are plastids present even in plant roots where photosynthesis does not normally occur?
View Detailed Answer

Not all plastids are chloroplasts. Roots may contain colourless leucoplasts, which store food such as starch, oils or proteins. Therefore the absence of photosynthesis does not imply the absence of plastids.

15
Explain the relationship between vacuoles, cell firmness and wilting.
View Detailed Answer

The large central vacuole stores cell sap containing water and other dissolved substances. Water in the vacuole contributes to internal pressure and cellular firmness. During water shortage, vacuoles lose water, the cells become less firm and the plant may wilt.

16
What did J. Craig Venter’s synthetic DNA experiment demonstrate, and what did it not demonstrate?
View Detailed Answer

The experiment showed that laboratory-synthesised DNA could direct the growth and division of a recipient bacterial cell, supporting the role of DNA in controlling cellular structure and activities.

It did not represent creation of an entirely new cell from non-living chemicals because the cytoplasm, membrane and other cell components came from an existing living cell.

17
State three biological roles of cell division.
View Detailed Answer
  • Growth by increasing cell number.
  • Repair and replacement of damaged or dead cells.
  • Reproduction: mitosis can support asexual reproduction, while meiosis produces gametes for sexual reproduction.
18
Explain why chromosome number is halved during meiosis and restored during fertilisation.
View Detailed Answer

Meiosis produces gametes with half the chromosome number of the parent cell. During fertilisation, two gametes combine. Their chromosome sets together restore the original chromosome number, preventing chromosome number from doubling in every generation.

19
State the contributions of Schleiden, Schwann and Virchow to Cell Theory.
View Detailed Answer
  • Matthias Schleiden, 1838: reported that plants are made of cells.
  • Theodor Schwann, 1839: concluded that animals are also made of cells.
  • Rudolf Virchow, 1855: stated that new cells arise only from pre-existing cells.
20
Explain how salt and sugar can help preserve foods such as pickles or murabbas using the concept of osmosis.
View Detailed Answer

A high concentration of salt or sugar creates a strongly concentrated external environment. Water tends to move out of cells of many spoilage-causing microorganisms by osmosis. Loss of available water makes conditions unfavourable for their normal growth and multiplication, thereby helping preserve the food.

Section D – 15 Four-Mark Questions

Detailed explanations, experimental analysis and competency questions.

1
Describe how the size of an onion peel cell can be estimated using a microscope field of view.
View Detailed Answer
  1. Measure the diameter of the microscope’s circular field using a transparent ruler.
  2. Convert the measured field diameter from millimetres to micrometres using 1 mm = 1000 µm.
  3. Observe an onion peel and count how many cells lie in one straight line across the field diameter.
  4. Divide field diameter in micrometres by number of cells.
Estimated cell size = Field diameter in µm ÷ Number of cells across diameter

For example, 5000 µm ÷ 25 = 200 µm.

2
Explain the fluid-mosaic model and relate its structure to selective permeability.
View Detailed Answer
  • The cell membrane is about 7–10 nm thick and consists mainly of lipids and proteins.
  • Lipids form a bilayer, with water-attracting heads outward and water-repelling tails inward.
  • Various proteins are embedded in this bilayer.
  • Membrane molecules can move, so the membrane is fluid, while the mixture of molecular components gives the mosaic description.

The embedded proteins can act as gatekeepers, helping regulate movement of particular substances and therefore contributing to selective permeability.

3
Compare the response of plant and animal cells to a concentrated sugar solution and explain the role of the cell wall.
View Detailed Answer

Water moves out of both plant and animal cells by osmosis because the external solution is concentrated.

  • In a plant cell, the inner content contracts and the plasma membrane moves away from the wall, but the rigid cell wall preserves the cell’s outer form.
  • An animal cell has no cell wall, so the entire cell can shrink considerably.

The comparison demonstrates the supporting and shape-maintaining function of the plant cell wall.

4
Prepare a detailed comparison between prokaryotic and eukaryotic cells.
View Detailed Answer
FeatureProkaryoticEukaryotic
NucleusNo membrane-bound nucleus; nucleoid presentWell-defined membrane-bound nucleus
Typical diameterAbout 1–10 µmAbout 10–100 µm
Membrane-bound organellesAbsentPresent
OrganisationUsually unicellularCan be unicellular or multicellular

Both nevertheless contain fundamental cellular components such as plasma membrane, cytoplasm, genetic material and ribosomes.

5
Describe the nucleus and explain how its internal structures participate in heredity and protein production.
View Detailed Answer
  • The nucleus has a double-layered nuclear membrane containing pores.
  • The nucleolus produces ribosomal subunits that later assemble in the cytoplasm.
  • The nucleus contains DNA, which carries genetic information.
  • Functional DNA segments are genes. In non-dividing cells DNA forms chromatin, which condenses into chromosomes before division.

Thus the nucleus combines genetic control with an important role in production of cellular protein-making machinery.

6
A pancreatic gland cell secretes large amounts of protein. Predict the organelles likely to be particularly active and explain their coordinated roles.
View Detailed Answer
  • Nucleolus: supplies ribosomal subunits.
  • Ribosomes/RER: synthesize proteins intended for secretion.
  • Golgi apparatus: modifies, sorts and packages these proteins into vesicles.
  • Mitochondria: provide ATP needed for active cellular work.

The organelles therefore form a coordinated manufacturing, processing and energy-supply system.

7
Compare mitochondria and chloroplasts structurally and functionally.
View Detailed Answer
FeatureMitochondrionChloroplast
MembranesDouble membraneDouble membrane
Own DNA/ribosomesPresentPresent
Internal featureInner membrane forms cristaeContains stroma and chlorophyll-bearing membrane structures
Main roleCellular respiration and ATP productionPhotosynthesis and sugar formation

Both can produce some of their own proteins because they contain DNA and ribosomes.

8
Explain how chloroplasts, chromoplasts, leucoplasts and vacuoles perform complementary functions in plants.
View Detailed Answer
  • Chloroplasts: capture light and participate in food synthesis.
  • Chromoplasts: supply bright colours to many flowers and fruits, helping attract pollinators or seed-dispersing animals.
  • Leucoplasts: store food such as starch, oils or proteins.
  • Vacuoles: store water, minerals, sugars and waste materials and help maintain cellular firmness.
9
Explain the significance of mitosis in the life of a multicellular organism.
View Detailed Answer
  • It increases cell number during growth.
  • It replaces lost or dead cells.
  • It repairs damaged tissues, such as after a cut.
  • It produces daughter cells with essentially the same DNA and chromosome number, helping maintain genetic continuity among body cells.
10
Explain meiosis and why its chromosome reduction is essential for sexual reproduction.
View Detailed Answer

Meiosis occurs in cells of reproductive organs and consists of two successive divisions.

  • After the first division, chromosome number is reduced to half.
  • A second division produces four daughter cells.
  • Each gamete therefore contains half the parental chromosome number.
  • When male and female gametes unite during fertilisation, the normal chromosome number is restored.

This mechanism also contributes to variation among offspring.

11
What could happen if mitosis or meiosis occurs incorrectly?
View Detailed Answer

Errors in mitosis:

  • May produce abnormal chromosome numbers in body cells.
  • Loss of normal division control can contribute to abnormal growth and tumours.

Errors in meiosis:

  • May cause genetic disorders or developmental problems.
  • May contribute to reduced fertility or early pregnancy loss.
12
Explain the onion root-tip experiment for observing dividing cells and why root tips are suitable.
View Detailed Answer

Fresh onion roots are grown, fixed/preserved, softened using dilute HCl, stained with aceto-carmine and gently squashed beneath a coverslip before microscopic observation.

Root tips are suitable because they contain actively growing cells that divide continuously. Consequently, a single prepared root-tip sample may contain cells displaying different structural stages of division.

13
Describe classical Cell Theory and explain how it links growth with continuity of life.
View Detailed Answer

Classical Cell Theory states:

  1. All living organisms consist of one or more cells.
  2. The cell is the basic structural and functional unit of living beings.
  3. All cells arise from pre-existing cells.

The third principle links growth, repair and reproduction with cell division and explains how cellular life continues from existing cells.

14
Explain contact inhibition, cancerous growth and programmed cell death as three aspects of cellular population control.
View Detailed Answer
  • Contact inhibition: many normal animal cells stop dividing when they contact neighbouring cells.
  • Cancer: abnormal cells may lose growth control and continue to divide, potentially forming tumours.
  • Programmed Cell Death: genetically controlled removal of selected cells helps normal development and quality control.

Together these show that healthy tissues depend on a balance between cell production and cell removal.

15
Describe cell culture and mention four factors or applications associated with it.
View Detailed Answer

Cell culture is the growth of plant or animal cells outside the organism in controlled conditions using a nutrient-rich medium.

Important requirements include suitable temperature, appropriate acidic/alkaline conditions, moisture and sterile conditions.

Applications include studying cellular functions and production of biochemicals, foods, medicines and vaccines.

Section E – 5 Competency-Based Case Studies

Integrated interpretation, experimental and application questions.

Case Study 1 – The Potato Investigation

Osmosis • Experimental Controls • Cell Membrane
Two nearly equal potato pieces are weighed. Piece A is placed in plain water, while Piece B is placed in 20% salt solution. After one hour, A has gained mass and appears swollen, whereas B has lost mass and appears smaller.

(a) Name the process responsible.

(b) Explain why Piece A gains water.

(c) Explain why Piece B loses water.

(d) Why should the two pieces initially be roughly equal?

(e) What cellular property does the experiment demonstrate?

View Detailed Case Study Solution

(a) Osmosis.

(b) Plain water is relatively dilute, so water moves into the cells across their selectively permeable plasma membranes.

(c) The concentrated salt solution contains less available water relative to the cell interior, so water moves out of the cells.

(d) Equal initial size and measured initial mass make comparison fair and help isolate the solution as the variable responsible for the observed difference.

(e) It demonstrates selective permeability of the cell membrane and osmotic movement of water.

Case Study 2 – A Protein-Secreting Cell

Ribosomes • ER • Golgi • Mitochondria
A gland cell produces large quantities of a protein and releases it outside the cell. Electron microscopy reveals abundant ribosomes, rough endoplasmic reticulum, Golgi stacks, vesicles and mitochondria.

(a) Where does protein synthesis occur?

(b) Why is RER abundant?

(c) State the role of Golgi apparatus.

(d) Why may many mitochondria be present?

(e) Give the approximate pathway of the secreted protein.

View Detailed Case Study Solution

(a) Ribosomes.

(b) RER bears ribosomes and is strongly involved in protein production and secretion.

(c) Golgi modifies, sorts and packages proteins into vesicles.

(d) Cellular synthesis, transport and secretion require energy. Mitochondria provide ATP.

(e) Ribosome/RER → ER → Golgi apparatus → Vesicle → Plasma membrane

Case Study 3 – The Mystery Cell

Prokaryotic vs Eukaryotic • Cell Structures
A scientist observes a cell approximately 4 µm in diameter. It has a plasma membrane, cytoplasm, ribosomes and genetic material, but no membrane-bound nucleus, mitochondria or Golgi apparatus.

(a) Is it more likely prokaryotic or eukaryotic?

(b) What is the region containing its genetic material called?

(c) Why can it still make proteins?

(d) Why can it carry out life processes despite lacking membrane-bound organelles?

(e) Give one size-based observation supporting your identification.

View Detailed Case Study Solution

(a) Prokaryotic.

(b) Nucleoid.

(c) It contains ribosomes, which are sites of protein synthesis.

(d) In prokaryotic cells, many cellular activities take place directly in the cytoplasm rather than in separate membrane-bound compartments.

(e) A diameter of 4 µm falls within the chapter’s typical prokaryotic range of about 1–10 µm.

Case Study 4 – Healing a Cut

Mitosis • Meiosis • Cell Division
A child develops a shallow cut on the skin. After several days, the damaged region is repaired. The child wonders why skin cells cannot use meiosis for this repair.

(a) Which type of division normally supports repair?

(b) How many daughter cells does it produce?

(c) What happens to chromosome number?

(d) Why would meiosis be unsuitable?

(e) State another role of mitosis.

View Detailed Case Study Solution

(a) Mitosis.

(b) Two daughter cells.

(c) Daughter cells retain the same chromosome number as the parent cell.

(d) Meiosis produces four cells with half the chromosome number and is specialised for gamete formation rather than replacement of ordinary body cells.

(e) Mitosis is also important in normal growth, maintenance and some forms of asexual reproduction.

Case Study 5 – Preserving Amla and Lemon

Osmosis • Food Preservation • Application
A farmer converts surplus amla and lemons into pickles, murabba and sharbat using relatively high concentrations of salt, sugar or jaggery. The products last much longer than untreated fresh produce.

(a) Which cellular process helps explain the preservation method?

(b) What type of external environment does concentrated salt or sugar create for microbial cells?

(c) What happens to water in many microbial cells?

(d) Why does this restrict spoilage?

(e) Mention two broader benefits described by the case.

View Detailed Case Study Solution

(a) Osmosis.

(b) A strongly concentrated or hypertonic external environment.

(c) Water tends to move out of microbial cells.

(d) Loss of water creates conditions unsuitable for normal growth and multiplication of many spoilage-causing microbes.

(e) Reduction of post-harvest waste and increased farmer income are two important benefits; it can also strengthen local food security and agro-processing.

Section F – 25 Dedicated Olympiad & HOTS Questions

These questions use the concepts of the chapter in unfamiliar situations, experiments, logical deductions and multi-step problems.

1
A microscope field has a diameter of 3.6 mm. Eighteen cells fit across its diameter. Under a second objective, only six cells of the same type fit across the apparent field. What can you infer about the relative field diameter?
Olympiad
View Solution

The original cell size is:

3600 µm ÷ 18 = 200 µm

If only six cells fit across the second field:

Second field diameter = 6 × 200 = 1200 µm = 1.2 mm

Thus the second visible field has one-third the diameter of the first field. Greater magnification generally shows a smaller field of view.

2
Student A says, “A 1000X image must show more useful information than a 500X image.” Student B disagrees. Who has the better argument?
View Solution

Student B has the better argument. Magnification only describes enlargement. If resolution or contrast is poor, increasing magnification may simply produce a larger blurred image. Useful microscopy therefore requires adequate magnification, resolution and contrast together.

3
Two identical cells are placed in solutions P and Q. Cell P shows no visible size change. Cell Q shrinks. Compare the external solute concentrations with the cell interior.
View Solution

Solution P is approximately isotonic with the cell, so external and internal solute concentrations are similar and there is no substantial net osmotic change.

Solution Q is hypertonic relative to the cell. It contains a higher solute concentration, causing water to leave the cell.

4
A plant cell and animal cell of similar internal concentration are placed in the same strong salt solution. Which observation best distinguishes the function of a cell wall?
View Solution

Both lose water. The animal cell shrinks as a whole. In the plant cell, the inner cellular content contracts but the rigid outer cell wall largely maintains the external shape. This contrast demonstrates the structural-support role of the cell wall.

5
A soaked mung bean is transferred to a strongly concentrated sugar solution. Predict its likely change and justify it.
View Solution

The seed is expected to lose water and become less swollen because the external solution has a higher solute concentration. Water therefore moves outward through selectively permeable cell membranes by osmosis.

6
A membrane suddenly loses most of its functional proteins while the lipid bilayer remains. Which property described by the fluid-mosaic model would be most directly disturbed?
View Solution

Selective transport would be strongly affected because membrane proteins act as gatekeepers for passage of many substances. The membrane boundary may still physically exist because the lipid bilayer remains, but its regulated exchange functions would be impaired.

7
A cell is 5 µm wide, lacks a membrane-bound nucleus and contains ribosomes. Is absence of mitochondria evidence that the cell cannot release energy from food?
View Solution

No. Its size and lack of a true nucleus suggest a prokaryotic cell. The chapter states that prokaryotic cells carry out many cellular activities directly in the cytoplasm even though they lack membrane-bound organelles. Absence of mitochondria therefore does not mean the cell is non-living or incapable of energy-releasing processes.

8
A newly discovered cell contains a nucleus, mitochondria, Golgi apparatus, ribosomes and no cell wall. What is the strongest conclusion?
View Solution

It is a eukaryotic cell because it possesses a membrane-bound nucleus and membrane-bound organelles. The absence of a cell wall makes it more consistent with an animal-type cell than a typical plant cell.

9
If a mature human RBC suddenly regained a functional nucleus, what trade-off might occur according to the chapter’s explanation of RBC specialisation?
View Solution

A nucleus could potentially restore greater capacity for cellular control, repair or division, but it would occupy space that is normally available for haemoglobin. The specialised advantage of carrying more haemoglobin—and therefore more oxygen—would be reduced.

10
A mutation prevents chromatin from organising into chromosomes before division. Which major process described in the chapter would be most directly threatened?
View Solution

Accurate cell division would be threatened. Before division, chromatin normally becomes organised into chromosomes. Failure to organise genetic material properly would interfere with orderly distribution of DNA to daughter cells.

11
A cell possesses normal DNA but its nucleolus is destroyed. Predict a major downstream difficulty.
View Solution

The nucleolus normally synthesises ribosomal subunits. Damage to it would therefore reduce formation of new ribosomes. Since ribosomes are required for protein synthesis, protein production would eventually be impaired even if the DNA itself remained intact.

12
A secretory protein is synthesised normally, but the Golgi apparatus stops functioning. Predict two consequences.
View Solution
  • The protein may not be properly modified, sorted or packaged for its correct destination.
  • Formation and transport of secretory vesicles would be impaired, so effective secretion through the plasma membrane would decrease.
13
If lysosomal enzymes became non-functional while all other organelles initially remained normal, what long-term cellular problem would you expect?
View Solution

Waste materials and damaged or worn-out cellular components would accumulate because lysosomes would no longer efficiently break them down. Recycling of useful breakdown products would also decrease, eventually disturbing overall cellular health.

14
A muscle cell requires very large amounts of ATP. Would one huge mitochondrion necessarily be more efficient than many smaller mitochondria? Explain using surface-area reasoning.
View Solution

Not necessarily. Numerous smaller mitochondria can collectively provide a large membrane surface area and distribute energy-producing capacity throughout the cell. Within each mitochondrion, folding of the inner membrane into cristae further increases reaction surface area. A single giant organelle could reduce this distributed surface advantage.

15
A plant leaf cell has functioning chloroplasts but all mitochondria become non-functional. Can the cell be considered normal simply because it can still make sugar?
View Solution

No. Chloroplasts help synthesise food, whereas mitochondria release usable energy from food during cellular respiration and store it in ATP. Sugar production alone cannot replace the mitochondrial role in supplying ATP for most cellular activities.

16
A flower loses all chromoplast pigments but retains healthy chloroplasts in its green tissues. Which ecological function described in the chapter may be affected?
View Solution

Bright colours produced by chromoplast pigments can help attract pollinators. Loss of such pigments in flowers could therefore reduce visual attraction of pollinating organisms, even if photosynthesis elsewhere in the plant remained normal.

17
A potato tuber is kept underground and contains no green chloroplasts. A student concludes that its cells contain no plastids. Identify the error.
View Solution

The student incorrectly treats “plastid” as synonymous with “chloroplast”. Underground storage tissues may contain colourless leucoplasts. The chapter specifically notes leucoplasts in potato cells that store starch.

18
If a plant cell’s central vacuole permanently lost its ability to retain water, predict two effects even if the cell wall remained intact.
View Solution
  • Internal pressure supporting cellular firmness would fall.
  • Plant tissues could become less firm and the plant could wilt despite retaining the rigid cell-wall framework.

Storage of dissolved substances in cell sap would also be disturbed.

19
Synthetic DNA is inserted into a cell whose own DNA has been removed, and the cell begins dividing according to the inserted DNA. Why does this not prove that scientists created life completely from non-living matter?
View Solution

Only the DNA was synthesised. The recipient cell membrane, cytoplasm, ribosomes and other necessary cellular machinery were obtained from a pre-existing living cell. The experiment therefore demonstrates the controlling role of DNA but not creation of an entire living cell from non-living components.

20
A body cell has 24 chromosomes. Compare the chromosome number expected in daughter cells after normal mitosis and in gametes produced by meiosis.
View Solution

After normal mitosis, each daughter cell retains the same chromosome number as the parent:

Mitosis → 24 chromosomes per daughter cell

Meiosis reduces chromosome number to half:

Meiosis → 12 chromosomes per gamete
21
What would happen over generations if gametes were formed by ordinary mitosis and therefore retained the full chromosome number?
View Solution

If each gamete retained the full parental chromosome number, fusion of two gametes would produce a fertilised cell with approximately twice the normal chromosome number. Repetition in later generations could cause chromosome number to increase repeatedly. Meiosis avoids this by halving the chromosome number before fertilisation.

22
Skin cells of an organism unexpectedly begin undergoing meiosis rather than mitosis during wound repair. Predict why repair would fail to maintain normal tissue.
View Solution

Meiosis produces four cells with half the chromosome number and is specialised for gamete formation. Tissue repair requires daughter cells genetically and chromosomally comparable to normal body cells. Therefore meiotic products would not properly replace ordinary skin cells.

23
Two cultures contain identical normal animal cells. In Culture A, cells stop dividing after forming a continuous layer. In Culture B, cells pile upon one another. What cellular control may have been lost in B?
View Solution

Culture B may have lost normal contact inhibition. Normal animal cells often stop dividing when they contact neighbouring cells. Loss of this control allows continued division and accumulation of abnormal cell masses, a behaviour associated with tumour formation.

24
During embryo development, the cells between future fingers fail to undergo programmed cell death. Predict the structural result.
View Solution

Cells between developing digits would remain rather than being selectively removed. Consequently the fingers could remain connected by tissue, producing a webbed appearance. The example shows why controlled cell death is as important as controlled cell division.

25
A scientist isolates a mature plant cell from a permanent tissue and, under suitable nutrient and environmental conditions, obtains an entire plant from it. Which concept does this support and why is it significant?
Olympiad Final Challenge
View Solution

The observation supports totipotency, the ability of a living plant cell to give rise to a complete plant when provided with suitable conditions.

The idea was associated in the chapter with Gottlieb Haberlandt and became foundational to plant tissue culture technology. It demonstrates that even a specialised plant cell can retain the genetic information required to generate an entire organism under appropriate conditions.

Exam-Focused Rapid Revision

  • Cell: basic structural and functional unit of life.
  • Robert Hooke: observed cork cells in 1665.
  • Human-eye resolution: approximately 0.1 mm at about 25 cm.
  • Cell size: field diameter ÷ number of cells across the diameter.
  • Total microscope magnification: eyepiece × objective.
  • Plasma membrane: thin, selectively permeable, lipid-protein membrane.
  • Osmosis: diffusion of water across a selectively permeable membrane.
  • Cell wall: rigid but permeable outer layer; plant walls are primarily cellulose.
  • Prokaryote: no membrane-bound nucleus or membrane-bound organelles.
  • Eukaryote: well-defined nucleus and membrane-bound organelles.
  • Nucleus: contains genetic material; genes are functional segments of DNA.
  • Ribosome: protein synthesis.
  • RER: proteins; SER: lipids and certain hormones.
  • Golgi: modifies, sorts and packages cellular products.
  • Lysosome: intracellular breakdown and recycling.
  • Mitochondrion: cellular respiration and ATP production.
  • Chloroplast: photosynthesis.
  • Chromoplast: coloured pigments.
  • Leucoplast: storage of food.
  • Vacuole: storage and support; large central vacuole contributes to plant-cell firmness.
  • Mitosis: two genetically similar daughter cells with unchanged chromosome number.
  • Meiosis: four daughter cells with half chromosome number.
  • Cell Theory: organisms consist of cells; cell is basic unit; cells arise from pre-existing cells.
  • Contact inhibition: normal control limiting excessive animal-cell division.
  • Programmed Cell Death: genetically regulated selective destruction of cells.
  • Totipotency: potential of a suitable plant cell to regenerate a complete plant.

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