SK Tuitions • Class 8 Mathematics
Proportional Reasoning-1 — 80 Question Bank with Detailed Solutions
A comprehensive practice bank covering proportional change, ratios, simplest form, equivalent ratios, cross multiplication, Rule of Three, direct-proportion applications, unequal sharing, mixtures, unit conversions, unit rates and competency-based reasoning.
Topics Covered
<details>, so they continue to work even if a WordPress setup blocks JavaScript. JavaScript below only adds search, section filtering and expand/collapse controls.Section A — One-Mark Questions
30 questions • Fundamentals, MCQs, short answers and quick reasoning
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Step 1: HCF of 42 and 56 is 14.
Step 2: Divide both terms by 14:
Answer: 3 : 4
(a) 10 : 12 (b) 15 : 20 (c) 20 : 28 (d) 25 : 30
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Multiply both terms of 5 : 7 by 4:
Answer: (c) 20 : 28
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Use cross multiplication:
Answer: x = 30
(a) a + d = b + c (b) ad = bc (c) ac = bd (d) a − b = c − d
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For two proportional ratios, the cross products are equal.
Answer: (b) ad = bc
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The scale factor is 20 ÷ 8 = 2.5. The height must change by the same factor.
Answer: 30 cm
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False. For example, 2 : 3 is not proportional to 3 : 4 because
Equivalent ratios are obtained by multiplying or dividing both terms by the same non-zero factor, not generally by adding the same number.
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HCF of 600 and 900 is 300.
Answer: 2 : 3
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By the standard volume conversion used in the chapter:
Answer: 1000 mL
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Answer: 43,560 square feet
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Use F = (9/5)C + 32.
Answer: 77°F
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HCF(72, 96) = 24.
Answer: 3 : 4
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21 : 27 simplifies by dividing by 3:
So the ratios are proportional.
Answer: Yes
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Divide both terms by 5:
Answer: 1 : 34
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Total parts = 3 + 1 = 4. Value of one part = ₹280 ÷ 4 = ₹70.
Answer: ₹210
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Total parts = 3 + 5 = 8. One part = 64 ÷ 8 = 8 L.
Answer: 24 L
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HCF(15, 35) = 5.
Answer: 3 : 7
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Regular coffee has decoction fraction 15/(15+35) = 15/50 = 0.30.
The second cup has decoction fraction 20/(20+30) = 20/50 = 0.40.
Since 0.40 > 0.30, the second cup contains a greater proportion of decoction.
Answer: Stronger
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Regular decoction fraction = 15/50 = 0.30.
New decoction fraction = 10/50 = 0.20.
Since 0.20 < 0.30, it has less decoction per cup.
Answer: Lighter
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Tea A: 200 g costs ₹200, so 1000 g costs 5 × ₹200 = ₹1000.
Tea B: 1000 g costs ₹800.
Answer: Tea B is cheaper per kilogram.
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40 is one-third of 120, so the rice must also be one-third.
Answer: 5 kg
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Since ad = bc, divide both sides by a:
Answer: d = bc/a
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Answer: 3.281 feet
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Answer: 10.764 square feet
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Answer: 10,000 square metres
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Answer: 2.471 acres
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Initially: 3 : 30 = 1 : 10.
Nine years later: 12 : 39 = 4 : 13.
Since 1 : 10 ≠ 4 : 13, the ratio changes.
Answer: No
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HCF(60, 40) = 20.
Answer: 3 : 2
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Distance per minute = 90/150 = 0.6 km.
Answer: 36 km
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Check cross products:
The cross products are equal.
Answer: True
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Both ratios simplify to 3 : 1.
Answer: True
Section B — Two-Mark Questions
10 questions • Short working and direct applications
(i) x : 42 (ii) 6 : y.
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(i) 21 becomes 42 by multiplying by 2. Therefore 14 must also be multiplied by 2.
(ii) 14 becomes 6 by multiplying by 6/14 = 3/7. Apply the same factor to 21.
Answer: x = 28, y = 9
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Simplify each ratio.
Since their simplest forms are identical, the ratios are proportional.
Answer: Yes, they are proportional.
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First rectangle:
Second rectangle:
The corresponding side ratios match.
Answer: Yes, the rectangles are similar.
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Total parts = 2 + 3 = 5.
Answer: ₹1,800 and ₹2,700
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Total parts = 1 + 5 = 6.
Answer: 40 mL acid and 200 mL water
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Convert 2 kg to 2000 g. The quantity factor is 2000 ÷ 500 = 4.
Answer: ₹1,680
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Convert 2.5 L to 2500 mL.
2500 mL is 2500 ÷ 500 = 5 times 500 mL.
Answer: 75 seconds
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Use C = (5/9)(F − 32).
Answer: 20°C
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Cost of one notebook:
Cost of 12 notebooks:
Answer: ₹540
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Capacity of one bus = 162 ÷ 3 = 54 people.
For 204 people:
So 3 buses are not enough; a fourth bus is required. The fourth bus will carry only 42 people.
Answer: 4 buses; no, all four will not be full.
Section C — Three-Mark Questions
10 questions • Multi-step proportional reasoning
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Glasses and sugar are directly proportional when sweetness remains the same.
24 is 4 times 6, so sugar must also be multiplied by 4.
Cross-check: 6 × 40 = 240 and 10 × 24 = 240.
Answer: 40 spoons
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Compare length : cement.
Both use one bag for every 20 ft of wall. Therefore the cement usage per unit length is the same.
Answer: No. Their length-to-cement ratios are proportional.
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Total parts = 5 + 3 = 8.
Check: ₹1050 + ₹630 = ₹1680.
Answer: ₹1,050 and ₹630
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Investment ratio:
Total parts = 4, so one part = ₹12,000 ÷ 4 = ₹3,000.
Answer: A = ₹9,000; B = ₹3,000
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First find the original amounts. Total parts = 5 + 3 = 8.
Sand remains 30 kg. For the new ratio 3 : 2:
Cement to add = 20 − 18 = 2 kg.
Answer: 2 kg of cement
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From the first pair:
The second pair confirms it: 30/4 = 7.5.
Therefore y = 7.5x.
Answer: 52.5, 75; constant y/x = 7.5
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Find the cost per kilogram:
Then for 5 kg:
Equivalently, 2.4 : 168 :: 5 : x gives x = (5 × 168)/2.4 = 350.
Answer: ₹350
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City A density:
City B density:
Since 4000 > 3000, City B has more people per square kilometre.
Answer: City B is more crowded.
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Half an acre is one-half of 43,560 ft².
Answer: 21,780 square feet
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Set up a direct proportion between money and quantity:
The money factor is:
Therefore the saffron quantity is also 21 times:
Answer: 52.5 palas
Section D — Five-Mark Questions
10 questions • Detailed application problems
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Step 1: Find the scale factor.
Step 2: Scale every ingredient by the same factor.
Step 3: Verify the rice : dal ratio.
The same factor was applied to both quantities, so the ratio is preserved.
Answer: 2.25 kg rice, 750 g dal, 1.875 kg vegetables; rice : dal remains 3 : 1.
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Step 1: Add all wall lengths.
Step 2: Set up the proportion.
Step 3: Cross multiply.
Check by unit rate: 1450 ÷ 10 = 145 bricks/ft; 145 × 108 = 15,660.
Answer: Approximately 15,660 bricks
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For equal volumes:
(i) For 1 L: water mass = 1 kg.
(ii) For 3 L of gold:
(iii) 3 L of water has mass 3 kg.
Answer: (i) 18.5 kg, (ii) 55.5 kg, (iii) 52.5 kg heavier
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Step 1: Find the plot area.
Step 2: Convert the plot area to acres.
Step 3: Apply 10 tonnes per acre.
Step 4: Convert tonnes to kilograms.
Answer: About 22.96 tonnes, or 22,956.8 kg
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Step 1: Split the mass in the ratio 3 : 1. Total parts = 4.
Step 2: Convert grams to kilograms.
Step 3: Find metal costs.
Answer: 5.805 g copper, 1.935 g nickel; total metal cost ≈ ₹7.85.
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First convert/identify a common rate.
(i) 4 hours = 240 minutes.
(ii) Time for 216 km:
Answer: (i) 144 km, (ii) 360 minutes = 6 hours
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(i) Original mixture: Total parts = 3 + 5 = 8.
(ii) After adding 20 mL yellow:
(iii) Restore 3 : 5. With 45 mL yellow, let required blue be x.
Blue already present = 15 mL, so blue to add = 27 − 15 = 12 mL.
Answer: (i) 15 mL blue, 25 mL yellow; (ii) 1 : 3; (iii) add 12 mL blue.
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Step 1: Simplify the investment ratio.
Step 2: Find distributable profit.
Step 3: Share ₹28,000 in the ratio 3 : 2.
Check: ₹16,800 + ₹11,200 = ₹28,000.
Answer: A = ₹16,800; B = ₹11,200
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Step 1: Convert volumes to mL.
(i) 10 L bucket:
(ii) 18 L tank:
Why proportional? The flow rate is constant, so multiplying the volume by a factor multiplies the filling time by the same factor.
Answer: (i) 5 min, (ii) 9 min
(a) 8 pens cost ₹120; find the cost of 18 pens at the same price per pen.
(b) Two people are 10 and 30 years old; compare their age ratio now and after 5 years.
(c) A 120 km journey takes 3 h at 40 km/h. At 60 km/h, does time increase in the same proportion as speed?
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(a) Direct proportion. Price per pen is constant.
(b) Not a direct proportion over time.
Adding the same number to both ages does not preserve the ratio.
(c) Not direct proportion. For a fixed distance, increasing speed reduces time.
Thus speed changes 40 → 60 (factor 1.5), while time changes 3 → 2 (it decreases). The direct Rule of Three model must not be used as if both increased together.
Answer: (a) Direct, ₹270; (b) not direct; (c) not direct, 2 h.
Section E — Assertion–Reason
10 questions • Conceptual reasoning
Reason (R): Both ratios simplify to 2 : 3.
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6 : 9 = 2 : 3 and 14 : 21 = 2 : 3. Therefore both A and R are true, and R correctly explains A.
Answer: Option A
Reason (R): Multiplying both terms of a ratio by the same non-zero factor gives an equivalent ratio.
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The assertion is false. Example: 2 : 3 becomes 7 : 8 after adding 5, and 2 : 3 ≠ 7 : 8.
The reason is true: equivalent ratios can be formed by multiplying both terms by the same non-zero factor.
Answer: Option D
Reason (R): Proportional ratios always satisfy a + c = b + d.
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The assertion is true because proportional ratios have equal cross products.
The reason is false; equality of sums is not a condition for proportion.
Answer: Option C
Reason (R): Their simplest forms are 1 : 1 and 5 : 4 respectively.
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The assertion is false because the simplified ratios are different.
The reason is true:
Answer: Option D
Reason (R): 3 × 20 = 5 × 12.
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Both cross products equal 60, so the ratios are proportional. The reason gives the exact test used to prove the assertion.
Answer: Option A
Reason (R): 5 × 20 is not equal to 7 × 15.
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The assertion is false.
The reason is true and shows why the ratios are not proportional.
Answer: Option D
Reason (R): 1 litre is equal to 1000 mL.
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The assertion is true because:
The reason is also true, but it is unrelated to temperature conversion and does not explain the assertion.
Answer: Option B
Reason (R): Both width-to-height ratios simplify to 3 : 2.
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60 : 40 = 3 : 2 and 90 : 60 = 3 : 2. Both statements are true, and the reason explains why the rectangles have the same width-to-height proportion.
Answer: Option A
Reason (R): Adding the same number to both terms of a ratio does not necessarily preserve the ratio.
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The assertion is false. Example: ages 10 and 30 are 1 : 3, but after 10 years they are 20 : 40 = 1 : 2.
The reason is true.
Answer: Option D
Reason (R): The shares are mx/(m+n) and nx/(m+n).
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Both statements are true. Add the two shares:
Thus R correctly explains A.
Answer: Option A
Section F — Case Studies
10 case studies • Competency-based applications
(i) Simplify the regular ratio. (ii) Classify A–E as regular, stronger or lighter. (iii) If 60 mL decoction is used for regular coffee, how much milk is needed?
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(i) Regular ratio:
Regular coffee has decoction fraction 3/(3+7) = 3/10 = 0.30.
(ii) Classification:
- A: 300 : 600 = 1 : 2. Decoction fraction = 1/3 ≈ 0.333, so stronger.
- B: 150 : 500 = 3 : 10. Decoction fraction = 3/13 ≈ 0.231, so lighter.
- C: 200 : 400 = 1 : 2. Decoction fraction = 1/3 ≈ 0.333, so stronger.
- D: 24 : 56 = 3 : 7, so regular.
- E: 100 : 300 = 1 : 3. Decoction fraction = 1/4 = 0.25, so lighter.
(iii) For regular coffee, 3 : 7 :: 60 : x.
Answer: Regular = 3 : 7; A strong, B light, C strong, D regular, E light; milk = 140 mL.
(i) Which of P, Q and R preserve the original proportions? (ii) Find the height of S so it is proportional. (iii) Explain why reducing both original dimensions by the same number of millimetres need not preserve shape.
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Original width : height:
(i)
(ii) For S:
Width doubles, so height must also double.
(iii) Proportional resizing requires multiplication by the same factor. Subtracting, for example, 20 mm gives 40 × 20, whose ratio is 2 : 1, not 3 : 2.
Answer: P and Q preserve shape; R does not; S height = 80 mm.
(i) Find rice and dal needed for 80 students. (ii) Find both quantities for 200 students. (iii) Verify that the rice : dal ratio is unchanged.
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The quantities scale with the number of students.
(i) 120 → 80 has factor 80/120 = 2/3.
(ii) 120 → 200 has factor 200/120 = 5/3.
(iii) Verify ratio:
Answer: 80 students: 10 kg rice, 4 kg dal; 200 students: 25 kg rice, 10 kg dal; ratio remains 5 : 2.
(i) Are volume and price proportional for the sachet and small bottle? (ii) Among the three bottles only, which has the lowest price per mL? (iii) If the 1000 mL bottle were priced in direct proportion to the 180 mL bottle, what would its price be approximately?
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(i) Compare ratios.
Since 1 : 30 ≠ 1 : 77, price is not proportional to volume for these packs.
(ii) Price per mL among bottles:
So the large bottle has the lowest unit price among the bottles.
(iii) Direct-proportion price based on small bottle:
Answer: Not proportional; large bottle is cheapest per mL among bottles; proportional 1000 mL price ≈ ₹855.56.
(i) Find the initial blue and yellow amounts. (ii) Find the new ratio after adding yellow. (iii) How much blue must be added afterward to restore the original 3 : 5 ratio?
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(i) Total parts = 8, so one part = 40/8 = 5 mL.
(ii) After adding 20 mL yellow:
(iii) Let final blue amount be x while yellow stays 45 mL.
Blue to add = 27 − 15 = 12 mL.
Answer: 15 mL blue, 25 mL yellow; new ratio 1 : 3; add 12 mL blue.
(i) Find the capacity of one bus. (ii) How many buses are needed for 204 people, and will all be full? (iii) How many buses are needed for 270 people so that all are full? (iv) What is the minimum number for 325 people?
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(i)
(ii)
So 4 buses are needed; the last has 42 people, so not all are full.
(iii)
Exactly 5 buses, all full.
(iv) Six buses hold 6 × 54 = 324 people, which is one short. Therefore 7 buses are required.
Answer: 54 per bus; 4 buses for 204 (not all full); 5 for 270; 7 for 325.
(i) Find the approximate cost of 2,400 ft². (ii) Find the cost of 0.25 acre. (iii) Explain why the price-area relationship is directly proportional under the assumption of a fixed price per unit area.
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(i) Cost of 2400 ft²:
So the approximate cost is ₹82,645.
(ii) 0.25 acre:
(iii) With a constant price per square foot, multiplying area by a factor multiplies cost by the same factor, which is the defining pattern of direct proportion.
Answer: About ₹82,645; ₹3,75,000; cost is directly proportional to area at constant unit price.
(i) Find the approximate population density of each city. (ii) Which is more crowded by this measure? (iii) Why is comparing only total population insufficient?
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(i) Delhi density:
Mumbai density:
(ii) Mumbai has the higher population per square kilometre, so it is more crowded by this measure.
(iii) Total population ignores land area. A city with fewer people can still be more crowded if those people occupy a much smaller area.
Answer: Delhi ≈ 20,216/km²; Mumbai ≈ 36,364/km²; Mumbai is more crowded.
(i) Simplify the orange : apple ratio. (ii) To make 3 L of the same drink, find the amount of each juice. (iii) Convert 25°C to Fahrenheit.
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(i)
(ii) Total ratio parts = 2 + 3 = 5. Convert 3 L = 3000 mL.
(iii)
Answer: 2 : 3; 1.2 L orange and 1.8 L apple; 77°F.
(i) Find the mass of each metal in one coin. (ii) Find the approximate metal cost of one coin. (iii) Estimate the metal cost for 1,000 such coins at the same rates.
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(i) Split 7.74 g in the ratio 3 : 1.
(ii) Convert to kilograms and price each metal.
(iii) For 1,000 coins:
Answer: 5.805 g Cu, 1.935 g Ni; ≈ ₹7.85 per coin; ≈ ₹7,854.17 for 1,000 coins.

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