SK Tuitions • Class 8 Mathematics

Proportional Reasoning-1 — 80 Question Bank with Detailed Solutions

A comprehensive practice bank covering proportional change, ratios, simplest form, equivalent ratios, cross multiplication, Rule of Three, direct-proportion applications, unequal sharing, mixtures, unit conversions, unit rates and competency-based reasoning.

80Total questions
30 + 301-mark + 2/3/5-mark
10Assertion–Reason
10Case studies

Topics Covered

Similarity in proportional change Ratios & terms Simplest form using HCF Equivalent ratios Cross multiplication Trairāśika / Rule of Three Direct proportion Comparing unit rates Sharing in a ratio Profit & mixture sharing Length, area & volume conversions Celsius–Fahrenheit conversion When direct proportion does not apply
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Section A — One-Mark Questions

30 questions • Fundamentals, MCQs, short answers and quick reasoning

Q1
1 mark Ratios
Simplify the ratio 42 : 56 to its lowest terms.
Click to view solution

Step 1: HCF of 42 and 56 is 14.

Step 2: Divide both terms by 14:

42 ÷ 14 : 56 ÷ 14 = 3 : 4

Answer: 3 : 4

Q2
1 mark Equivalent ratios Exemplar-inspired
Which of the following is proportional to 5 : 7?
(a) 10 : 12   (b) 15 : 20   (c) 20 : 28   (d) 25 : 30
Click to view solution

Multiply both terms of 5 : 7 by 4:

5 × 4 : 7 × 4 = 20 : 28

Answer: (c) 20 : 28

Q3
1 mark Missing term
Find x if 18 : 24 :: x : 40.
Click to view solution

Use cross multiplication:

18 × 40 = 24x
x = (18 × 40) ÷ 24 = 30

Answer: x = 30

Q4
1 mark Cross multiplication
If a : b :: c : d, which relation must be true?
(a) a + d = b + c   (b) ad = bc   (c) ac = bd   (d) a − b = c − d
Click to view solution

For two proportional ratios, the cross products are equal.

a/b = c/d ⇒ ad = bc

Answer: (b) ad = bc

Q5
1 mark Similarity & scaling Exemplar-inspired
A photograph is 8 cm wide and 12 cm high. It is enlarged proportionally to a width of 20 cm. What should its new height be?
Click to view solution

The scale factor is 20 ÷ 8 = 2.5. The height must change by the same factor.

12 × 2.5 = 30 cm

Answer: 30 cm

Q6
1 mark Ratio reasoning
True or False: Adding the same non-zero number to both terms of a ratio always gives an equivalent ratio.
Click to view solution

False. For example, 2 : 3 is not proportional to 3 : 4 because

2 × 4 = 8, but 3 × 3 = 9.

Equivalent ratios are obtained by multiplying or dividing both terms by the same non-zero factor, not generally by adding the same number.

Q7
1 mark Simplest form
Write 600 mL : 900 mL in simplest form.
Click to view solution

HCF of 600 and 900 is 300.

600 ÷ 300 : 900 ÷ 300 = 2 : 3

Answer: 2 : 3

Q8
1 mark Unit conversion
Complete: 1 litre = ______ mL.
Click to view solution

By the standard volume conversion used in the chapter:

1 L = 1000 mL

Answer: 1000 mL

Q9
1 mark Unit conversion
Complete: 1 acre = ______ square feet.
Click to view solution
1 acre = 43,560 ft²

Answer: 43,560 square feet

Q10
1 mark Temperature conversion
Convert 25°C to Fahrenheit.
Click to view solution

Use F = (9/5)C + 32.

F = (9/5) × 25 + 32 = 45 + 32 = 77°F

Answer: 77°F

Q11
1 mark Simplest form
Reduce 72 : 96 to its simplest form.
Click to view solution

HCF(72, 96) = 24.

72 ÷ 24 : 96 ÷ 24 = 3 : 4

Answer: 3 : 4

Q12
1 mark Proportion check Exemplar-inspired
Are 7 : 9 and 21 : 27 proportional?
Click to view solution

21 : 27 simplifies by dividing by 3:

21 : 27 = 7 : 9

So the ratios are proportional.

Answer: Yes

Q13
1 mark Ratios
A school has 5 teachers for 170 students. Write the teacher-to-student ratio in simplest form.
Click to view solution

Divide both terms by 5:

5 : 170 = 1 : 34

Answer: 1 : 34

Q14
1 mark Sharing in a ratio
₹280 is shared in the ratio 3 : 1. What is the larger share?
Click to view solution

Total parts = 3 + 1 = 4. Value of one part = ₹280 ÷ 4 = ₹70.

Larger share = 3 × ₹70 = ₹210

Answer: ₹210

Q15
1 mark Sharing in a ratio
A 64 L mixture contains two liquids in the ratio 3 : 5. How much of the first liquid is present?
Click to view solution

Total parts = 3 + 5 = 8. One part = 64 ÷ 8 = 8 L.

First liquid = 3 × 8 = 24 L

Answer: 24 L

Q16
1 mark Mixtures
Simplify the coffee-decoction-to-milk ratio 15 : 35.
Click to view solution

HCF(15, 35) = 5.

15 : 35 = 3 : 7

Answer: 3 : 7

Q17
1 mark Mixtures
Regular coffee uses decoction : milk = 15 : 35. A second cup uses 20 : 30. Is the second cup stronger or lighter?
Click to view solution

Regular coffee has decoction fraction 15/(15+35) = 15/50 = 0.30.

The second cup has decoction fraction 20/(20+30) = 20/50 = 0.40.

Since 0.40 > 0.30, the second cup contains a greater proportion of decoction.

Answer: Stronger

Q18
1 mark Mixtures
Regular coffee uses decoction : milk = 15 : 35. A cup uses 10 : 40. Is this cup stronger or lighter than regular coffee?
Click to view solution

Regular decoction fraction = 15/50 = 0.30.

New decoction fraction = 10/50 = 0.20.

Since 0.20 < 0.30, it has less decoction per cup.

Answer: Lighter

Q19
1 mark Unit rate
Tea A costs ₹200 for 200 g. Tea B costs ₹800 for 1 kg. Which is cheaper per kilogram?
Click to view solution

Tea A: 200 g costs ₹200, so 1000 g costs 5 × ₹200 = ₹1000.

Tea B: 1000 g costs ₹800.

Answer: Tea B is cheaper per kilogram.

Q20
1 mark Rule of Three
120 students need 15 kg of rice. At the same rate, how much rice is needed for 40 students?
Click to view solution

40 is one-third of 120, so the rice must also be one-third.

15 ÷ 3 = 5 kg

Answer: 5 kg

Q21
1 mark Cross multiplication
In a : b :: c : d, express d in terms of a, b, and c.
Click to view solution

Since ad = bc, divide both sides by a:

d = bc/a

Answer: d = bc/a

Q22
1 mark Unit conversion
According to the conversion used in the chapter, 1 metre is approximately how many feet?
Click to view solution
1 m ≈ 3.281 ft

Answer: 3.281 feet

Q23
1 mark Unit conversion
According to the conversion used in the chapter, 1 square metre is approximately how many square feet?
Click to view solution
1 m² ≈ 10.764 ft²

Answer: 10.764 square feet

Q24
1 mark Unit conversion
Complete: 1 hectare = ______ square metres.
Click to view solution
1 hectare = 10,000 m²

Answer: 10,000 square metres

Q25
1 mark Unit conversion
According to the chapter, 1 hectare is approximately how many acres?
Click to view solution
1 hectare ≈ 2.471 acres

Answer: 2.471 acres

Q26
1 mark Age ratios
When Neelima is 3 years old, her mother is 30. Nine years later their ages are 12 and 39. Is the ratio of their ages unchanged?
Click to view solution

Initially: 3 : 30 = 1 : 10.

Nine years later: 12 : 39 = 4 : 13.

Since 1 : 10 ≠ 4 : 13, the ratio changes.

Answer: No

Q27
1 mark Similarity & ratios
An image measures 60 mm × 40 mm. What is its width-to-height ratio in simplest form?
Click to view solution

HCF(60, 40) = 20.

60 : 40 = 3 : 2

Answer: 3 : 2

Q28
1 mark Direct proportion Exemplar-inspired
A car travels 90 km in 150 minutes at constant speed. How far will it travel in 60 minutes?
Click to view solution

Distance per minute = 90/150 = 0.6 km.

Distance in 60 min = 0.6 × 60 = 36 km

Answer: 36 km

Q29
1 mark Proportion check
True or False: 4 : 7 :: 12 : 21.
Click to view solution

Check cross products:

4 × 21 = 84 and 7 × 12 = 84

The cross products are equal.

Answer: True

Q30
1 mark Proportion check
True or False: 24 : 8 :: 9 : 3.
Click to view solution

Both ratios simplify to 3 : 1.

24 : 8 = 3 : 1 and 9 : 3 = 3 : 1

Answer: True

Section B — Two-Mark Questions

10 questions • Short working and direct applications

Q31
2 marks Equivalent ratios Exemplar-inspired
Complete both ratios so that each is proportional to 14 : 21:
(i) x : 42    (ii) 6 : y.
Click to view solution

(i) 21 becomes 42 by multiplying by 2. Therefore 14 must also be multiplied by 2.

x = 14 × 2 = 28

(ii) 14 becomes 6 by multiplying by 6/14 = 3/7. Apply the same factor to 21.

y = 21 × (3/7) = 9

Answer: x = 28, y = 9

Q32
2 marks Proportion check Exemplar-inspired
Check whether 45 : 60 and 27 : 36 are proportional. Show a method.
Click to view solution

Simplify each ratio.

45 : 60 = 3 : 4
27 : 36 = 3 : 4

Since their simplest forms are identical, the ratios are proportional.

Answer: Yes, they are proportional.

Q33
2 marks Similarity & scaling
Two rectangular designs measure 84 cm × 56 cm and 120 cm × 80 cm. Are they similar on the basis of width-to-height ratio?
Click to view solution

First rectangle:

84 : 56 = 3 : 2

Second rectangle:

120 : 80 = 3 : 2

The corresponding side ratios match.

Answer: Yes, the rectangles are similar.

Q34
2 marks Sharing in a ratio
Divide ₹4,500 in the ratio 2 : 3.
Click to view solution

Total parts = 2 + 3 = 5.

Value of one part = ₹4500 ÷ 5 = ₹900
First share = 2 × ₹900 = ₹1800
Second share = 3 × ₹900 = ₹2700

Answer: ₹1,800 and ₹2,700

Q35
2 marks Mixtures & sharing
Acid and water are mixed in the ratio 1 : 5. Find the amount of each in 240 mL of solution.
Click to view solution

Total parts = 1 + 5 = 6.

One part = 240 ÷ 6 = 40 mL
Acid = 1 × 40 = 40 mL
Water = 5 × 40 = 200 mL

Answer: 40 mL acid and 200 mL water

Q36
2 marks Direct proportion
500 g of tea costs ₹420. What will 2 kg cost at the same rate?
Click to view solution

Convert 2 kg to 2000 g. The quantity factor is 2000 ÷ 500 = 4.

Cost = ₹420 × 4 = ₹1680

Answer: ₹1,680

Q37
2 marks Volume & proportion
A tap fills 500 mL in 15 seconds. At the same flow rate, how long will it take to fill 2.5 L?
Click to view solution

Convert 2.5 L to 2500 mL.

2500 mL is 2500 ÷ 500 = 5 times 500 mL.

Time = 15 × 5 = 75 seconds

Answer: 75 seconds

Q38
2 marks Temperature conversion
Convert 68°F to Celsius.
Click to view solution

Use C = (5/9)(F − 32).

C = (5/9)(68 − 32) = (5/9) × 36 = 20°C

Answer: 20°C

Q39
2 marks Direct proportion Exemplar-inspired
5 identical notebooks cost ₹225. Find the cost of 12 notebooks at the same price per notebook.
Click to view solution

Cost of one notebook:

₹225 ÷ 5 = ₹45

Cost of 12 notebooks:

12 × ₹45 = ₹540

Answer: ₹540

Q40
2 marks Direct proportion
Three identical buses were completely full with 162 people. If 204 people travel this year, how many such buses are needed? Will all buses be full?
Click to view solution

Capacity of one bus = 162 ÷ 3 = 54 people.

For 204 people:

204 ÷ 54 = 3 remainder 42

So 3 buses are not enough; a fourth bus is required. The fourth bus will carry only 42 people.

Answer: 4 buses; no, all four will not be full.

Section C — Three-Mark Questions

10 questions • Multi-step proportional reasoning

Q41
3 marks Rule of Three Exemplar-inspired
A lemonade recipe uses 10 spoons of sugar for 6 glasses. How many spoons are required for 24 glasses if the sweetness is unchanged?
Click to view solution

Glasses and sugar are directly proportional when sweetness remains the same.

6 : 10 :: 24 : x

24 is 4 times 6, so sugar must also be multiplied by 4.

x = 10 × 4 = 40

Cross-check: 6 × 40 = 240 and 10 × 24 = 240.

Answer: 40 spoons

Q42
3 marks Proportion reasoning
Nitin uses 3 bags of cement for a 60 ft wall. Hari uses 2 bags for a 40 ft wall of the same height and thickness. Does Hari use less cement per unit length? Justify.
Click to view solution

Compare length : cement.

Nitin: 60 : 3 = 20 : 1
Hari: 40 : 2 = 20 : 1

Both use one bag for every 20 ft of wall. Therefore the cement usage per unit length is the same.

Answer: No. Their length-to-cement ratios are proportional.

Q43
3 marks Sharing in a ratio
Divide ₹1,680 in the ratio 5 : 3.
Click to view solution

Total parts = 5 + 3 = 8.

One part = ₹1680 ÷ 8 = ₹210
First share = 5 × ₹210 = ₹1050
Second share = 3 × ₹210 = ₹630

Check: ₹1050 + ₹630 = ₹1680.

Answer: ₹1,050 and ₹630

Q44
3 marks Profit sharing
A and B invest ₹75,000 and ₹25,000 respectively. They share a profit of ₹12,000 in the ratio of their investments. Find each share.
Click to view solution

Investment ratio:

75,000 : 25,000 = 3 : 1

Total parts = 4, so one part = ₹12,000 ÷ 4 = ₹3,000.

A’s share = 3 × ₹3000 = ₹9000
B’s share = 1 × ₹3000 = ₹3000

Answer: A = ₹9,000; B = ₹3,000

Q45
3 marks Mixture adjustment
A 48 kg mixture contains sand and cement in the ratio 5 : 3. How much cement must be added so that the new ratio of sand to cement becomes 3 : 2?
Click to view solution

First find the original amounts. Total parts = 5 + 3 = 8.

Sand = (5/8) × 48 = 30 kg
Cement = (3/8) × 48 = 18 kg

Sand remains 30 kg. For the new ratio 3 : 2:

3 : 2 :: 30 : x
x = (2/3) × 30 = 20 kg

Cement to add = 20 − 18 = 2 kg.

Answer: 2 kg of cement

Q46
3 marks Direct proportion Exemplar-inspired
The table represents a direct proportion. Complete it and state the constant ratio y/x.
x24710y1530??
Click to view solution

From the first pair:

y/x = 15/2 = 7.5

The second pair confirms it: 30/4 = 7.5.

Therefore y = 7.5x.

For x = 7, y = 7.5 × 7 = 52.5
For x = 10, y = 7.5 × 10 = 75

Answer: 52.5, 75; constant y/x = 7.5

Q47
3 marks Unit rate Exemplar-inspired
2.4 kg of rice costs ₹168. Find the cost of 5 kg at the same rate.
Click to view solution

Find the cost per kilogram:

₹168 ÷ 2.4 = ₹70 per kg

Then for 5 kg:

5 × ₹70 = ₹350

Equivalently, 2.4 : 168 :: 5 : x gives x = (5 × 168)/2.4 = 350.

Answer: ₹350

Q48
3 marks Comparison by rate
City A has 2.4 million people in 800 km². City B has 1.8 million people in 450 km². Which city is more crowded? Use population per km².
Click to view solution

City A density:

2,400,000 ÷ 800 = 3,000 people/km²

City B density:

1,800,000 ÷ 450 = 4,000 people/km²

Since 4000 > 3000, City B has more people per square kilometre.

Answer: City B is more crowded.

Q49
3 marks Area conversion
Convert 0.5 acre into square feet using 1 acre = 43,560 ft².
Click to view solution

Half an acre is one-half of 43,560 ft².

0.5 × 43,560 = 21,780 ft²

Answer: 21,780 square feet

Q50
3 marks Rule of Three
An old merchant’s record says that 2.5 palas of saffron cost 3/7 niska. At the same rate, how many palas can be bought for 9 niskas?
Click to view solution

Set up a direct proportion between money and quantity:

(3/7) niska : 2.5 palas :: 9 niskas : x palas

The money factor is:

9 ÷ (3/7) = 9 × 7/3 = 21

Therefore the saffron quantity is also 21 times:

x = 2.5 × 21 = 52.5 palas

Answer: 52.5 palas

Section D — Five-Mark Questions

10 questions • Detailed application problems

Q51
5 marks Recipe scaling
A recipe for 6 people uses 900 g rice, 300 g dal and 750 g vegetables. The same recipe is to be prepared for 15 people. Find the required quantity of each ingredient and verify that the rice-to-dal ratio remains unchanged.
Click to view solution

Step 1: Find the scale factor.

15/6 = 2.5

Step 2: Scale every ingredient by the same factor.

Rice = 900 × 2.5 = 2250 g = 2.25 kg
Dal = 300 × 2.5 = 750 g
Vegetables = 750 × 2.5 = 1875 g = 1.875 kg

Step 3: Verify the rice : dal ratio.

Original = 900 : 300 = 3 : 1
New = 2250 : 750 = 3 : 1

The same factor was applied to both quantities, so the ratio is preserved.

Answer: 2.25 kg rice, 750 g dal, 1.875 kg vegetables; rice : dal remains 3 : 1.

Q52
5 marks Rule of Three
A mason must build walls whose total length is obtained by adding these segments: 12, 12, 12, 15, 9, 15, 9, 9, 9 and 6 feet. If 1450 bricks are needed for every 10 feet of wall, estimate the number of bricks required.
Click to view solution

Step 1: Add all wall lengths.

12 + 12 + 12 + 15 + 9 + 15 + 9 + 9 + 9 + 6 = 108 ft

Step 2: Set up the proportion.

10 ft : 1450 bricks :: 108 ft : x bricks

Step 3: Cross multiply.

10x = 1450 × 108
x = (1450 × 108)/10 = 15,660

Check by unit rate: 1450 ÷ 10 = 145 bricks/ft; 145 × 108 = 15,660.

Answer: Approximately 15,660 bricks

Q53
5 marks Ratio & mass
The masses of equal volumes of gold and water are in the ratio 37 : 2. If 1 L of water has a mass of 1 kg, find (i) the mass of 1 L of gold, (ii) the mass of 3 L of gold, and (iii) how much heavier 3 L of gold is than 3 L of water.
Click to view solution

For equal volumes:

Gold mass : Water mass = 37 : 2

(i) For 1 L: water mass = 1 kg.

37 : 2 :: x : 1
x = 37/2 = 18.5 kg

(ii) For 3 L of gold:

3 × 18.5 = 55.5 kg

(iii) 3 L of water has mass 3 kg.

Difference = 55.5 − 3 = 52.5 kg

Answer: (i) 18.5 kg, (ii) 55.5 kg, (iii) 52.5 kg heavier

Q54
5 marks Area conversion & proportion
A farmer applies 10 tonnes of manure per acre. His rectangular plot is 200 ft by 500 ft. Using 1 acre = 43,560 ft², find the manure required in tonnes and kilograms.
Click to view solution

Step 1: Find the plot area.

Area = 200 × 500 = 100,000 ft²

Step 2: Convert the plot area to acres.

Acres = 100,000/43,560 ≈ 2.29568 acres

Step 3: Apply 10 tonnes per acre.

Manure = 2.29568 × 10 ≈ 22.9568 tonnes

Step 4: Convert tonnes to kilograms.

22.9568 × 1000 ≈ 22,956.8 kg

Answer: About 22.96 tonnes, or 22,956.8 kg

Q55
5 marks Sharing & unit cost
A 7.74 g cupro-nickel coin contains copper and nickel in the ratio 3 : 1. Copper costs ₹906/kg and nickel costs ₹1,341/kg. Find the mass of each metal and the approximate cost of the metals in one coin.
Click to view solution

Step 1: Split the mass in the ratio 3 : 1. Total parts = 4.

Copper mass = (3/4) × 7.74 = 5.805 g
Nickel mass = (1/4) × 7.74 = 1.935 g

Step 2: Convert grams to kilograms.

Copper = 0.005805 kg; Nickel = 0.001935 kg

Step 3: Find metal costs.

Copper cost = 0.005805 × 906 ≈ ₹5.2593
Nickel cost = 0.001935 × 1341 ≈ ₹2.5948
Total ≈ ₹5.2593 + ₹2.5948 = ₹7.8541

Answer: 5.805 g copper, 1.935 g nickel; total metal cost ≈ ₹7.85.

Q56
5 marks Distance-time proportion Exemplar-inspired
A car travels 90 km in 150 minutes at constant speed. (i) How far will it travel in 4 hours? (ii) How long will it take to travel 216 km at the same speed?
Click to view solution

First convert/identify a common rate.

Speed = 90/150 = 0.6 km per minute

(i) 4 hours = 240 minutes.

Distance = 0.6 × 240 = 144 km

(ii) Time for 216 km:

Time = 216/0.6 = 360 minutes
360 minutes = 6 hours

Answer: (i) 144 km, (ii) 360 minutes = 6 hours

Q57
5 marks Mixture adjustment
Blue and yellow paints are mixed in the ratio 3 : 5 to make 40 mL of green paint. (i) Find the original amounts. (ii) If 20 mL yellow paint is added, find the new ratio. (iii) How much blue paint must then be added to restore the ratio 3 : 5?
Click to view solution

(i) Original mixture: Total parts = 3 + 5 = 8.

One part = 40/8 = 5 mL
Blue = 3 × 5 = 15 mL; Yellow = 5 × 5 = 25 mL

(ii) After adding 20 mL yellow:

Blue : Yellow = 15 : (25 + 20) = 15 : 45 = 1 : 3

(iii) Restore 3 : 5. With 45 mL yellow, let required blue be x.

x : 45 = 3 : 5
x = (3/5) × 45 = 27 mL

Blue already present = 15 mL, so blue to add = 27 − 15 = 12 mL.

Answer: (i) 15 mL blue, 25 mL yellow; (ii) 1 : 3; (iii) add 12 mL blue.

Q58
5 marks Profit sharing
A and B invest ₹84,000 and ₹56,000 in a business. At the end of a month the profit is ₹35,000. They first keep ₹7,000 as a reserve and share the remaining profit in the ratio of their investments. Find each person’s share of the distributed profit.
Click to view solution

Step 1: Simplify the investment ratio.

84,000 : 56,000 = 3 : 2

Step 2: Find distributable profit.

₹35,000 − ₹7,000 = ₹28,000

Step 3: Share ₹28,000 in the ratio 3 : 2.

Total parts = 5; one part = ₹28,000/5 = ₹5,600
A = 3 × ₹5,600 = ₹16,800
B = 2 × ₹5,600 = ₹11,200

Check: ₹16,800 + ₹11,200 = ₹28,000.

Answer: A = ₹16,800; B = ₹11,200

Q59
5 marks Volume & rate
A tap fills 500 mL in 15 seconds at a steady rate. Find the time to fill (i) a 10 L bucket and (ii) an 18 L tank. Also state why volume and time are proportional here.
Click to view solution

Step 1: Convert volumes to mL.

10 L = 10,000 mL; 18 L = 18,000 mL

(i) 10 L bucket:

10,000/500 = 20 times the volume
Time = 20 × 15 = 300 s = 5 min

(ii) 18 L tank:

18,000/500 = 36 times the volume
Time = 36 × 15 = 540 s = 9 min

Why proportional? The flow rate is constant, so multiplying the volume by a factor multiplies the filling time by the same factor.

Answer: (i) 5 min, (ii) 9 min

Q60
5 marks Direct vs non-direct situations Exemplar-inspired
Study the situations below. Decide whether the quantities can be modelled by direct proportion. Where possible, calculate the missing value.
(a) 8 pens cost ₹120; find the cost of 18 pens at the same price per pen.
(b) Two people are 10 and 30 years old; compare their age ratio now and after 5 years.
(c) A 120 km journey takes 3 h at 40 km/h. At 60 km/h, does time increase in the same proportion as speed?
Click to view solution

(a) Direct proportion. Price per pen is constant.

₹120/8 = ₹15 per pen
18 pens cost 18 × ₹15 = ₹270

(b) Not a direct proportion over time.

Now: 10 : 30 = 1 : 3
After 5 years: 15 : 35 = 3 : 7

Adding the same number to both ages does not preserve the ratio.

(c) Not direct proportion. For a fixed distance, increasing speed reduces time.

At 60 km/h, time = 120/60 = 2 h

Thus speed changes 40 → 60 (factor 1.5), while time changes 3 → 2 (it decreases). The direct Rule of Three model must not be used as if both increased together.

Answer: (a) Direct, ₹270; (b) not direct; (c) not direct, 2 h.

Section E — Assertion–Reason

10 questions • Conceptual reasoning

Assertion–Reason options: A — Both A and R are true and R is the correct explanation of A. B — Both A and R are true but R is not the correct explanation of A. C — A is true but R is false. D — A is false but R is true.
Q61
Assertion–Reason Equivalent ratios
Assertion (A): 6 : 9 and 14 : 21 are proportional.
Reason (R): Both ratios simplify to 2 : 3.
Click to view solution

6 : 9 = 2 : 3 and 14 : 21 = 2 : 3. Therefore both A and R are true, and R correctly explains A.

Answer: Option A

Q62
Assertion–Reason Ratio reasoning
Assertion (A): Adding 5 to both terms of any ratio keeps the ratio unchanged.
Reason (R): Multiplying both terms of a ratio by the same non-zero factor gives an equivalent ratio.
Click to view solution

The assertion is false. Example: 2 : 3 becomes 7 : 8 after adding 5, and 2 : 3 ≠ 7 : 8.

The reason is true: equivalent ratios can be formed by multiplying both terms by the same non-zero factor.

Answer: Option D

Q63
Assertion–Reason Cross multiplication
Assertion (A): If a : b :: c : d, then ad = bc.
Reason (R): Proportional ratios always satisfy a + c = b + d.
Click to view solution

The assertion is true because proportional ratios have equal cross products.

The reason is false; equality of sums is not a condition for proportion.

Answer: Option C

Q64
Assertion–Reason Unit price
Assertion (A): The ratios 200 g : ₹200 and 1000 g : ₹800 are proportional.
Reason (R): Their simplest forms are 1 : 1 and 5 : 4 respectively.
Click to view solution

The assertion is false because the simplified ratios are different.

The reason is true:

200 : 200 = 1 : 1; 1000 : 800 = 5 : 4

Answer: Option D

Q65
Assertion–Reason Proportion check
Assertion (A): 3 : 5 and 12 : 20 are proportional.
Reason (R): 3 × 20 = 5 × 12.
Click to view solution

Both cross products equal 60, so the ratios are proportional. The reason gives the exact test used to prove the assertion.

Answer: Option A

Q66
Assertion–Reason Proportion check
Assertion (A): 5 : 7 and 15 : 20 are proportional.
Reason (R): 5 × 20 is not equal to 7 × 15.
Click to view solution

The assertion is false.

5 × 20 = 100; 7 × 15 = 105

The reason is true and shows why the ratios are not proportional.

Answer: Option D

Q67
Assertion–Reason Unit conversion
Assertion (A): 25°C is equal to 77°F.
Reason (R): 1 litre is equal to 1000 mL.
Click to view solution

The assertion is true because:

F = (9/5) × 25 + 32 = 77°F

The reason is also true, but it is unrelated to temperature conversion and does not explain the assertion.

Answer: Option B

Q68
Assertion–Reason Similarity & ratios
Assertion (A): Rectangles of dimensions 60 × 40 and 90 × 60 have the same shape ratio.
Reason (R): Both width-to-height ratios simplify to 3 : 2.
Click to view solution

60 : 40 = 3 : 2 and 90 : 60 = 3 : 2. Both statements are true, and the reason explains why the rectangles have the same width-to-height proportion.

Answer: Option A

Q69
Assertion–Reason Age ratios
Assertion (A): If the ages of two people are in the ratio 1 : 3 today, the ratio will remain 1 : 3 after 10 years.
Reason (R): Adding the same number to both terms of a ratio does not necessarily preserve the ratio.
Click to view solution

The assertion is false. Example: ages 10 and 30 are 1 : 3, but after 10 years they are 20 : 40 = 1 : 2.

The reason is true.

Answer: Option D

Q70
Assertion–Reason Sharing in a ratio
Assertion (A): If a quantity x is divided in the ratio m : n, the two shares add up to x.
Reason (R): The shares are mx/(m+n) and nx/(m+n).
Click to view solution

Both statements are true. Add the two shares:

mx/(m+n) + nx/(m+n) = x(m+n)/(m+n) = x

Thus R correctly explains A.

Answer: Option A

Section F — Case Studies

10 case studies • Competency-based applications

Q71
Case study Coffee mixtures
Case Study 1 — Filter Coffee: A café treats decoction : milk = 15 : 35 as its regular coffee. It tests five mixtures: A = 300 : 600, B = 150 : 500, C = 200 : 400, D = 24 : 56, E = 100 : 300.

(i) Simplify the regular ratio. (ii) Classify A–E as regular, stronger or lighter. (iii) If 60 mL decoction is used for regular coffee, how much milk is needed?
Click to view solution

(i) Regular ratio:

15 : 35 = 3 : 7

Regular coffee has decoction fraction 3/(3+7) = 3/10 = 0.30.

(ii) Classification:

  • A: 300 : 600 = 1 : 2. Decoction fraction = 1/3 ≈ 0.333, so stronger.
  • B: 150 : 500 = 3 : 10. Decoction fraction = 3/13 ≈ 0.231, so lighter.
  • C: 200 : 400 = 1 : 2. Decoction fraction = 1/3 ≈ 0.333, so stronger.
  • D: 24 : 56 = 3 : 7, so regular.
  • E: 100 : 300 = 1 : 3. Decoction fraction = 1/4 = 0.25, so lighter.

(iii) For regular coffee, 3 : 7 :: 60 : x.

x = (7/3) × 60 = 140 mL

Answer: Regular = 3 : 7; A strong, B light, C strong, D regular, E light; milk = 140 mL.

Q72
Case study Image scaling Exemplar-inspired
Case Study 2 — Resizing an Image: An original image is 60 mm wide and 40 mm high. Four edited versions are P = 90 × 60, Q = 45 × 30, R = 80 × 50, and S has width 120 mm with unknown height.

(i) Which of P, Q and R preserve the original proportions? (ii) Find the height of S so it is proportional. (iii) Explain why reducing both original dimensions by the same number of millimetres need not preserve shape.
Click to view solution

Original width : height:

60 : 40 = 3 : 2

(i)

P: 90 : 60 = 3 : 2 → proportional
Q: 45 : 30 = 3 : 2 → proportional
R: 80 : 50 = 8 : 5 ≠ 3 : 2 → not proportional

(ii) For S:

60 : 40 :: 120 : h

Width doubles, so height must also double.

h = 80 mm

(iii) Proportional resizing requires multiplication by the same factor. Subtracting, for example, 20 mm gives 40 × 20, whose ratio is 2 : 1, not 3 : 2.

Answer: P and Q preserve shape; R does not; S height = 80 mm.

Q73
Case study School meal
Case Study 3 — Mid-Day Meal: For 120 students, a school kitchen uses 15 kg rice and 6 kg dal. Assume consumption is proportional to the number of students.

(i) Find rice and dal needed for 80 students. (ii) Find both quantities for 200 students. (iii) Verify that the rice : dal ratio is unchanged.
Click to view solution

The quantities scale with the number of students.

(i) 120 → 80 has factor 80/120 = 2/3.

Rice = 15 × 2/3 = 10 kg
Dal = 6 × 2/3 = 4 kg

(ii) 120 → 200 has factor 200/120 = 5/3.

Rice = 15 × 5/3 = 25 kg
Dal = 6 × 5/3 = 10 kg

(iii) Verify ratio:

15 : 6 = 5 : 2; 10 : 4 = 5 : 2; 25 : 10 = 5 : 2

Answer: 80 students: 10 kg rice, 4 kg dal; 200 students: 25 kg rice, 10 kg dal; ratio remains 5 : 2.

Q74
Case study Price vs quantity
Case Study 4 — Shampoo Packs: A shop lists the same shampoo as follows: 6 mL sachet ₹2; 180 mL small bottle ₹154; 340 mL medium bottle ₹276; 1000 mL large bottle ₹540.

(i) Are volume and price proportional for the sachet and small bottle? (ii) Among the three bottles only, which has the lowest price per mL? (iii) If the 1000 mL bottle were priced in direct proportion to the 180 mL bottle, what would its price be approximately?
Click to view solution

(i) Compare ratios.

Volume ratio = 6 : 180 = 1 : 30
Price ratio = 2 : 154 = 1 : 77

Since 1 : 30 ≠ 1 : 77, price is not proportional to volume for these packs.

(ii) Price per mL among bottles:

Small = 154/180 ≈ ₹0.856 per mL
Medium = 276/340 ≈ ₹0.812 per mL
Large = 540/1000 = ₹0.540 per mL

So the large bottle has the lowest unit price among the bottles.

(iii) Direct-proportion price based on small bottle:

x = 154 × (1000/180) ≈ ₹855.56

Answer: Not proportional; large bottle is cheapest per mL among bottles; proportional 1000 mL price ≈ ₹855.56.

Q75
Case study Paint mixture
Case Study 5 — Paint Shade: A painter makes 40 mL green paint by mixing blue and yellow in the ratio 3 : 5. Then 20 mL yellow is added.

(i) Find the initial blue and yellow amounts. (ii) Find the new ratio after adding yellow. (iii) How much blue must be added afterward to restore the original 3 : 5 ratio?
Click to view solution

(i) Total parts = 8, so one part = 40/8 = 5 mL.

Blue = 15 mL; Yellow = 25 mL

(ii) After adding 20 mL yellow:

15 : 45 = 1 : 3

(iii) Let final blue amount be x while yellow stays 45 mL.

x : 45 = 3 : 5 ⇒ x = 27 mL

Blue to add = 27 − 15 = 12 mL.

Answer: 15 mL blue, 25 mL yellow; new ratio 1 : 3; add 12 mL blue.

Q76
Case study Buses & capacity Exemplar-inspired
Case Study 6 — School Buses: Three identical buses carry 162 people when all are full.

(i) Find the capacity of one bus. (ii) How many buses are needed for 204 people, and will all be full? (iii) How many buses are needed for 270 people so that all are full? (iv) What is the minimum number for 325 people?
Click to view solution

(i)

Capacity = 162/3 = 54 people per bus

(ii)

204/54 = 3 remainder 42

So 4 buses are needed; the last has 42 people, so not all are full.

(iii)

270/54 = 5

Exactly 5 buses, all full.

(iv) Six buses hold 6 × 54 = 324 people, which is one short. Therefore 7 buses are required.

Answer: 54 per bus; 4 buses for 204 (not all full); 5 for 270; 7 for 325.

Q77
Case study Land & unit conversion
Case Study 7 — Land Price: One acre of land costs ₹15,00,000. Use 1 acre = 43,560 ft².

(i) Find the approximate cost of 2,400 ft². (ii) Find the cost of 0.25 acre. (iii) Explain why the price-area relationship is directly proportional under the assumption of a fixed price per unit area.
Click to view solution

(i) Cost of 2400 ft²:

43,560 ft² : ₹15,00,000 :: 2,400 ft² : x
x = 15,00,000 × 2400 / 43,560 ≈ ₹82,644.63

So the approximate cost is ₹82,645.

(ii) 0.25 acre:

₹15,00,000 × 0.25 = ₹3,75,000

(iii) With a constant price per square foot, multiplying area by a factor multiplies cost by the same factor, which is the defining pattern of direct proportion.

Answer: About ₹82,645; ₹3,75,000; cost is directly proportional to area at constant unit price.

Q78
Case study Population density
Case Study 8 — Which City Is More Crowded? Delhi has an area of 1,484 km² and population about 30 million. Mumbai has an area of 550 km² and population about 20 million.

(i) Find the approximate population density of each city. (ii) Which is more crowded by this measure? (iii) Why is comparing only total population insufficient?
Click to view solution

(i) Delhi density:

30,000,000 / 1,484 ≈ 20,216 people/km²

Mumbai density:

20,000,000 / 550 ≈ 36,364 people/km²

(ii) Mumbai has the higher population per square kilometre, so it is more crowded by this measure.

(iii) Total population ignores land area. A city with fewer people can still be more crowded if those people occupy a much smaller area.

Answer: Delhi ≈ 20,216/km²; Mumbai ≈ 36,364/km²; Mumbai is more crowded.

Q79
Case study Units & proportions
Case Study 9 — Fruit Drink and Temperature: A drink uses 600 mL orange juice and 900 mL apple juice. The kitchen is at 25°C.

(i) Simplify the orange : apple ratio. (ii) To make 3 L of the same drink, find the amount of each juice. (iii) Convert 25°C to Fahrenheit.
Click to view solution

(i)

600 : 900 = 2 : 3

(ii) Total ratio parts = 2 + 3 = 5. Convert 3 L = 3000 mL.

One part = 3000/5 = 600 mL
Orange = 2 × 600 = 1200 mL = 1.2 L
Apple = 3 × 600 = 1800 mL = 1.8 L

(iii)

F = (9/5) × 25 + 32 = 77°F

Answer: 2 : 3; 1.2 L orange and 1.8 L apple; 77°F.

Q80
Case study Alloy & cost
Case Study 10 — Cupro-Nickel Coin: A 7.74 g coin contains copper and nickel in the ratio 3 : 1. Copper costs ₹906/kg and nickel ₹1,341/kg.

(i) Find the mass of each metal in one coin. (ii) Find the approximate metal cost of one coin. (iii) Estimate the metal cost for 1,000 such coins at the same rates.
Click to view solution

(i) Split 7.74 g in the ratio 3 : 1.

Copper = (3/4) × 7.74 = 5.805 g
Nickel = (1/4) × 7.74 = 1.935 g

(ii) Convert to kilograms and price each metal.

Copper cost = 0.005805 × 906 ≈ ₹5.2593
Nickel cost = 0.001935 × 1341 ≈ ₹2.5948
Total per coin ≈ ₹7.8541 ≈ ₹7.85

(iii) For 1,000 coins:

₹7.854165 × 1000 ≈ ₹7,854.17

Answer: 5.805 g Cu, 1.935 g Ni; ≈ ₹7.85 per coin; ≈ ₹7,854.17 for 1,000 coins.

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